How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
An -narrow graph has a clique or stable set of size at least
Statement
Let be a nonempty finite graph and let . If is -narrow, then contains a clique or a stable set of size at least .
Facts & Assumptions
Given: A nonempty -narrow finite graph .
The graph has a perfect induced subgraph with (An -narrow graph contains a perfect induced subgraph of order at least ).
Every finite graph satisfies (The bounds and ).
In a perfect graph, every induced subgraph satisfies (A perfect graph).
The clique number and stability number are the sizes of the largest clique and stable set (Cliques, stable sets, the clique number and stability number ).
Real powers use the displayed exponent notation (Real powers for positive bases, with the zero-base positive-exponent convention).
Proof
Let be the perfect induced subgraph given by [L1]. Applying [L2] to and then using [F1] gives . Hence either or . So , and therefore , has a stable set or clique of size at least .
Since , step 1.1 yields a clique or stable set of size at least by [F3].
Depends on
- Cliques, stable sets, the clique number $\omega(G)$ and stability number $\alpha(G)$
- Real powers for positive bases, with the zero-base positive-exponent convention
- An $\alpha$-narrow graph contains a perfect induced subgraph of order at least $|V(G)|^{1/\alpha}$
- A perfect graph
- The bounds $\omega(G)\leq\chi(G)$ and $|V(G)|\leq\chi(G)\alpha(G)$
Used by
Dependency tree · two levels
23 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Maria Chudnovsky and Shmuel Safra, The Erdős-Hajnal conjecture for bull-free graphs, Proposition 2.1 (standard reference, not scraped)