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CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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An α-narrow graph has a clique or stable set of size at least V(G)1/(2α)

Statement

Let G be a nonempty finite graph and let α>0. If G is α-narrow, then G contains a clique or a stable set of size at least V(G)1/(2α).

Facts & Assumptions

Given: A nonempty α-narrow finite graph G.

[L1]

The graph G has a perfect induced subgraph P with V(P)V(G)1/α (An α-narrow graph contains a perfect induced subgraph of order at least V(G)1/α).

[L2]

Every finite graph H satisfies V(H)χ(H)α(H) (The bounds ω(G)χ(G) and V(G)χ(G)α(G)).

[F1]

In a perfect graph, every induced subgraph satisfies χ=ω (A perfect graph).

[F2]

The clique number and stability number are the sizes of the largest clique and stable set (Cliques, stable sets, the clique number ω(G) and stability number α(G)).

[F3]

Proof

technique · direct
1.1

Let P be the perfect induced subgraph given by [L1]. Applying [L2] to P and then using [F1] gives V(P)α(P)ω(P). Hence either α(P)V(P)1/2 or ω(P)V(P)1/2. So P, and therefore G, has a stable set or clique of size at least V(P)1/2.

L1L2F1F2algebra
2.1

Since V(P)V(G)1/α, step 1.1 yields a clique or stable set of size at least V(G)1/(2α) by [F3].

step 1.1L1F3algebra

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