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Conformal transport of continuous Dirichlet solutions

Statement

Let Ω,Ω′⊆C be bounded regular complex domains, let F:Ω→Ω′ be a conformal bijection that extends to a homeomorphism Ω‾→Ω′‾, and let φ:∂Ω′→R be continuous. If u is the unique continuous harmonic function on Ω‾ with boundary data φ∘F∣∂Ω, then v:=u∘F−1 is the unique continuous harmonic function on Ω′‾ with boundary data φ.

Facts & Assumptions

Given: Bounded regular complex domains Ω,Ω′, a closure-homeomorphic conformal bijection F:Ω→Ω′, and a continuous boundary datum φ:∂Ω′→R.

[L1]

On a regular bounded plane domain, Perron's method gives the unique continuous harmonic solution of the Dirichlet problem (On a regular bounded plane domain, Perron's method solves the Dirichlet problem).

[L2]

Harmonicity is preserved under holomorphic changes of coordinate (Plane harmonicity is preserved by holomorphic and antiholomorphic changes of coordinate).

[L3]

A bounded-domain continuous harmonic extension of fixed boundary data is unique (The bounded plane Dirichlet problem has at most one continuous harmonic solution).

Proof

technique · direct
1.1L1L2given

By [L1], the source datum φ∘F∣∂Ω has a unique continuous harmonic solution u on Ω‾. Define v=u∘F−1 on Ω′. Since F−1 is holomorphic on Ω′, [L2] makes v harmonic on Ω′.

2.1step 1.1given

The homeomorphic extension of F to the closures shows that F−1 extends continuously from Ω′‾ to Ω‾. Therefore v extends continuously to Ω′‾, and for ξ∈∂Ω′ one has [step 1.1, given] v(ξ)=u(F−1(ξ))=(φ∘F)(F−1(ξ))=φ(ξ). This identifies the transported boundary values.

3.1L2L3step 2.1

Let w be any other continuous harmonic function on Ω′‾ with boundary data φ. Then w∘F is continuous on Ω‾, harmonic on Ω by [L2], and has boundary values φ∘F on ∂Ω. By [L3], one has w∘F=u on Ω‾, hence w=v on Ω′‾.

4.1step 3.1∎

Thus v=u∘F−1 is exactly the unique Dirichlet solution on Ω′ with boundary data φ.

Depends on

Used by

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Sources