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Coordinate functionals of a Schauder basis are bounded
Statement
Assume DC. If is a Schauder basis of a Banach space , then every coordinate functional and every partial-sum projection is bounded. Moreover
Facts & Assumptions
The Axiom of Dependent Choice holds (The axiom of dependent choice: a relation in which every element is related to something admits an -indexed chain).
The coefficient space is Banach and its summation map is a bounded linear bijection (The Schauder coefficient space is Banach).
Under DC, a bounded linear bijection between Banach spaces has bounded inverse (Bounded inverse theorem).
and the basis constant is the supremum of their norms (Partial-sum projections and basis constant).
Proof
Given: The objects and hypotheses in the Statement.
Apply [L2] to [L1]. The only choice use is [A1], through that bounded-inverse [given, L2, L1, A1] theorem. Thus is bounded.
Truncation , , satisfies , because every partial sum of is a partial sum of . Since and ,
for every , including . Hence . [L1, L3, step 1.1]
For ,
Because , taking norms gives . Thus every is bounded. [L3, step 2.1] ∎
Depends on
Used by
Dependency tree · two levels
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Sources
- Thomas Schlumprecht, Course Notes in Functional Analysis, Math 655 (standard reference, not scraped)