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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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Coordinate functionals of a Schauder basis are bounded

Statement

Assume DC. If (en)n1 is a Schauder basis of a Banach space X, then every coordinate functional en and every partial-sum projection PN is bounded. Moreover

K:=supN0PN<.

Facts & Assumptions

[L1]

The coefficient space E is Banach and its summation map S:EX is a bounded linear bijection (The Schauder coefficient space is Banach).

[L2]

Under DC, a bounded linear bijection between Banach spaces has bounded inverse (Bounded inverse theorem).

[L3]

PNx=nNen(x)en and the basis constant is the supremum of their norms (Partial-sum projections and basis constant).

Proof

technique · direct

Given: The objects and hypotheses in the Statement.

1.1

Apply [L2] to [L1]. The only choice use is [A1], through that bounded-inverse [given, L2, L1, A1] theorem. Thus S1:XE is bounded.

A1L1L2
2.1

Truncation QN:EE, (an)(a1,,aN,0,), satisfies QNaEaE, because every partial sum of QNa is a partial sum of a. Since PN=SQNS1 and S1,

givenL1L3step 1.1

PNS1

for every N, including N=0. Hence K<. [L1, L3, step 1.1]

3.1

For n1,

givenL3step 2.1

en(x)en=(PnPn1)x.

Because en0, taking norms gives en(x)(Pn+Pn1)x/en. Thus every en is bounded. [L3, step 2.1] ∎

Depends on

Used by

Dependency tree · two levels

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Sources