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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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A Schauder basis implies the bounded approximation property

Statement

Assume DC. If a Banach space X has a Schauder basis with basis constant K, then X has K-BAP, and hence AP.

Facts & Assumptions

[L1]

Under DC, the partial-sum projections are bounded and satisfy sup⁡N∥PN∥=K<∞ (Coordinate functionals of a Schauder basis are bounded).

[L2]

By the defining expansion of a Schauder basis, PNx→x for every x∈X (Schauder basis and coordinate functionals).

[L3]

Uniformly bounded pointwise-convergent bounded operators converge uniformly on compact sets (Uniformly bounded pointwise-convergent operators converge uniformly on compact sets).

[L4]

K-BAP is compact-uniform approximation of the identity by finite-rank maps of norm at most K (Approximation property and bounded approximation property).

Proof

technique · direct

Given: The objects and hypotheses in the Statement.

1.1A1L1L2

Each PN has range in span⁡{e1,…,eN} and hence [given, L1, A1, L2] has finite rank. By [L1], using [A1] exactly through the coordinate-boundedness theorem, ∥PN∥≤K; by [L2], PNx→x for every x∈X.

2.1L3L4step 1.1∎

Apply [L3] to (PN) and the identity. On each compact C, [given, L3, L4, step 1.1] sup⁡x∈C∥PNx−x∥→0. Together with step 1.1, [L4] says precisely that X has K-BAP. Since BAP implies AP by [L4], the consequence follows.

Depends on

Used by

Dependency tree · two levels

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Sources