Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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The squared cross-product norm is the Gram determinant of two vectors

Statement

For u,vR3, u×v22=detG(u,v), and this value is positive exactly when u and v are linearly independent.

Equivalently, u×v22=u22v22u,v2.

Facts & Assumptions

Given: Vectors u,vR3.

[L1]

The cross product has the displayed coordinate formula, and it is bilinear, alternating, and orthogonal to its factors (The cross product in R3, The cross product is bilinear, alternating, and orthogonal to both factors).

[L2]

The two-vector Gram matrix has entries ui,uj, and its determinant is positive exactly for a linearly independent pair and zero exactly for a dependent pair (The Gram matrix G(v0,,vr1)=(vi,vj)i,j<r and Gram determinant, with empty value 1, A Gram determinant is nonnegative and is positive exactly when the vector list is linearly independent).

Proof

technique · direct
1.1

Expanding the three squared coordinates of u×v and collecting terms gives u×v22=(ux2+uy2+uz2)(vx2+vy2+vz2)(uxvx+uyvy+uzvz)2.

givenL1algebra
2.1

The right side of step 1.1 is u22v22u,v2=det(u,uu,vv,uv,v), which is detG(u,v) by [L2].

step 1.1L2algebra
3.1

The positivity and vanishing assertions follow from [L2], including the cases in which either vector is zero.

step 2.1L2

Depends on

Used by

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources