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The determinantal form of a Specht character

Statement

Let RS=⨁m≥0R(Sm) be the graded ordinary representation ring of the symmetric groups, whose multiplication is the outer induction product ∘ and whose unit is the trivial character of S0 (The graded ordinary representation ring of the symmetric groups, The outer induction product of symmetric-group characters). For m≥0 let [m]∈R(Sm) denote the trivial character of Sm (so [0] is the unit of RS), and set [m]:=0∈RS for m<0; the Frobenius characteristic ch⁡ is the degree-preserving ring isomorphism of The Frobenius characteristic is an isometric graded ring isomorphism normed by ch⁡(χν)=sν (The characteristic of a Specht character is a Schur function, The Frobenius characteristic map).

Then for every partition λ=(λ1≥⋯≥λk>0) of n, with χλ∈R(Sn) the character of the complex Specht module Sλ (Column antisymmetrizers, polytabloids, and Specht modules, Complex Specht modules are irreducible), χλ=det⁡([λi−i+j])1≤i,j≤kin RS, where the determinant is the Leibniz expansion det⁡([λi−i+j])=∑wsgn⁡(w) [λ1−1+w(1)]∘[λ2−2+w(2)]∘⋯∘[λk−k+w(k)] over the bijections w of {1,…,k}, with sgn⁡ the sign of the corresponding permutation (For n≥1, the determinant over a commutative ring by the Leibniz formula, and ∣det⁡A∣ for a real matrix, Inversions, inversion number, the sign sgn⁡(σ)=(−1)inv⁡(σ), and even and odd permutations). For every such w the degrees add up to ∑i=1k(λi−i+w(i))=∑iλi=n, so every nonzero monomial is homogeneous of degree n and the determinant is a well-defined element of R(Sn). For n=0 use λ=∅, k=0, and the empty determinant and empty product equal to [0]. The convention [0]=1 (the multiplicative identity of RS) must be distinguished from the zero element 0. No choice principle is used.

Facts & Assumptions

Given: A partition λ=(λ1≥⋯≥λk>0) of n, the graded ring RS=⨁m≥0R(Sm) with the outer product ∘ and unit the trivial character of S0, the elements [m]∈R(Sm) for m≥0 and [m]:=0 for m<0, and the characteristic map ch⁡.

[F1]

R(Sm) is the Z-span of the irreducible characters of Sm; RS is the direct sum with degree-m components, and under the outer product it is a commutative graded Z-algebra with unit the trivial character of S0 (The graded ordinary representation ring of the symmetric groups, The outer induction product of symmetric-group characters, The Frobenius characteristic is an isometric graded ring isomorphism). The outer product of elements of degrees a1,…,ak≥0 is homogeneous of degree a1+⋯+ak, and if some degree is negative the corresponding entry is 0 by the convention on [m].

[F2]

ch⁡:RS→Λ is a degree-preserving Z-module isomorphism, carries the outer product to the product in Λ and the unit to 1, and is therefore injective (The Frobenius characteristic is an isometric graded ring isomorphism, The Frobenius characteristic preserves outer products).

[F3]

ch⁡(χν)=sν for every n≥0 and every partition ν⊢n (The characteristic of a Specht character is a Schur function); for m≥1 the one-row Specht module is trivial, since its tabloid space has one basis vector and its column stabilizer is trivial (Column antisymmetrizers, polytabloids, and Specht modules). Thus ch⁡([m])=s(m) for m≥1; for m=0 use the empty partition and ch⁡([0])=1.

[F4]

Jacobi–Trudi: for r≥ℓ(λ), sλ=det⁡(hλi−i+j)1≤i,j≤r, where hq is the stable complete homogeneous function, h0=1, and hq=0 for q<0 (Jacobi–Trudi and dual Jacobi–Trudi identities). In particular s(m)=hm for every m≥1 by the case r=1; for the empty partition s∅=h0=1, and hm=0 for m<0.

[F5]

The determinant over a commutative ring is the Leibniz sum det⁡(A)=∑σsgn⁡(σ)∏iaσ(i),i of the entries (For n≥1, the determinant over a commutative ring by the Leibniz formula, and ∣det⁡A∣ for a real matrix, Inversions, inversion number, the sign sgn⁡(σ)=(−1)inv⁡(σ), and even and odd permutations); the equivalent row-indexed sum uses w=σ−1. Their signs agree: (i,j)↦(σ(j),σ(i)) bijects the inversions of σ with those of σ−1. A unital ring homomorphism φ sends the finite sums and products defining the determinant of A to those defining the determinant of the entrywise image φ(A).

Proof

technique · direct
1.1F3F4given

For every integer m one has ch⁡([m])=hm. For m≥1 this is ch⁡([m])=ch⁡(χ(m))=s(m)=hm by [F3] and the case r=1 of [F4]; for m=0 both sides are 1 by [F3] and [F4]; for m<0 both sides are 0, since [m]:=0 and ch⁡ is additive with ch⁡(0)=0, while hm=0 by the convention of [F4].

1.2F1F5algebra

Every bijection w of {1,…,k} satisfies ∑i(λi−i+w(i))=∑iλi=n, because ∑ii=∑iw(i). Hence the Leibniz term [λ1−1+w(1)]∘⋯∘[λk−k+w(k)] is a product of k homogeneous elements whose degrees sum to n: if every λi−i+w(i)≥0 it lies in the degree-n component R(Sn) of RS, and if some λi−i+w(i)<0 then the corresponding factor is the zero element, so the term is 0 by [F1]. For k=0 the sole empty term is [0]. The determinant det⁡H is the finite sum of these k! terms, hence is a well-defined element of the degree-n component R(Sn) of RS.

2.1step 1.1F1F2F3F4F5algebra

Let H be the k×k matrix with entries hij:=[λi−i+j]∈RS over the commutative ring RS of [F1]. Applying the unital ring homomorphism ch⁡ entrywise to H gives the matrix with entries ch⁡(hij)=hλi−i+j by step 1.1. Since ch⁡ preserves finite sums and products, it commutes with the Leibniz determinant [F5], so ch⁡(det⁡H)=det⁡(hλi−i+j)=sλ=ch⁡(χλ), where the middle equality is Jacobi–Trudi at r=k≥ℓ(λ) and the last is [F3].

3.1step 2.1step 1.2F1F2F3F4algebra∎

Since ch⁡ is injective by [F2], the equality ch⁡(det⁡H)=ch⁡(χλ) of step 2.1 gives det⁡H=χλ in RS, which is the asserted determinant identity. Finally [0]∈R(S0) is the trivial character of the trivial group and the identity of RS, with ch⁡([0])=h0=1, whereas the zero element 0∈RS satisfies ch⁡(0)=0; since 1≠0 in Λ and ch⁡ is injective on the degree-0 component, [0]≠0, so the two conventions are distinct.

Remarks

  • Where the two determinant conventions enter. The entries [λi−i+j] are zero as soon as the index λi−i+j is negative, so very few of the k! Leibniz terms survive; the terms that do survive all lie in the same degree-n component. The identity ∑i(λi−i+w(i))=n is the reason the determinant is an element of the homogeneous piece R(Sn) rather than of the whole graded ring.

  • The Jacobi–Trudi route. The proof transports the Jacobi–Trudi determinant for Schur functions through the characteristic isomorphism, which is the reason the statement is an identity in RS rather than a numerical formula: the theorem is the character-theoretic mirror of sλ=det⁡(hλi−i+j). James's §19 expansion of the same determinant is an independent combinatorial proof of the identical identity and is the source recorded for the statement.

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