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The convergence and absolute-convergence abscissae differ by at most one
Statement
For every Dirichlet series, its abscissae satisfy
in the extended real line.
Facts & Assumptions
Given: A Dirichlet series with abscissae and .
The two abscissae are defined by right-half-plane convergence and absolute convergence (The convergence and absolute-convergence abscissae of a Dirichlet series).
Convergence at one point gives convergence on the entire open half-plane to its right (Convergence at one point of a Dirichlet series forces local uniform convergence on the open half-plane to its right).
Proof
Absolute convergence implies ordinary convergence term by term, so every half-plane counted for is also counted for . Therefore .
Let be any point of convergence and write . Then the terms tend to , so they are bounded: for some . Hence for every with , for some , and the right-hand side is summable. Thus absolute convergence holds throughout .
Since step 1.2 applies at every point of convergence, taking infima in [L1] gives . Combined with step 1.1, this is the claimed gap bound.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Leonard Tomczak, Analytic Number Theory, Theorem 3.4 (standard reference, not scraped)
- Kiran S. Kedlaya, Notes on Analytic Number Theory, Lemma 2.2 (standard reference, not scraped)