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TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
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The local Dolbeault lemma on nested polydiscs

Statement

Assume AC. Let n≥1, let P=∏j=1nDj and P′=∏j=1nDj′ be finite open coordinate polydiscs such that each closed coordinate disc Dj′‾ is a compact subset of Dj. Let 0≤p≤n and 1≤q≤n, and let η∈Ωp,q(P) be a smooth form with ∂ˉη=0. Then there is a smooth ψ∈Ωp,q−1(P′) such that ∂ˉψ=η∣P′.

Facts & Assumptions

Given: Full AC; P=∏j=1nDj and P′=∏j=1nDj′ are finite open polydiscs with each closed coordinate disc Dj′‾ compactly contained in Dj; 0≤p≤n, 1≤q≤n, and η∈Ωp,q(P) is smooth and ∂ˉ-closed.

[F1]

The dzI∧dzˉJ expansion is unique, and the coefficient formula for ∂ˉ differentiates the coefficients in zˉj and wedges dzˉj before their type factors (Bigraded complex forms and the Dolbeault operators).

[F2]

The graded product rule holds for ∂ˉ (The d, partial and dbar identities).

[F3]
[F4]

Under full AC, on a smaller coordinate polydisc the parameterized one-variable transform Tka is smooth, satisfies ∂zˉkTka=a, and preserves any selected equations ∂zˉℓa=0 with ℓ≠k (Local Cauchy transform with smooth parameters).

[F5]

Full AC means every family of nonempty sets has a choice function, and the local Cauchy-transform supplier explicitly assumes AC (The Axiom of Choice, Local Cauchy transform with smooth parameters).

Proof

technique · direct
1.1F1givenalgebra

If η=0, take ψ=0. Otherwise, by the unique type expansion [F1], some barred coordinate occurs. Let k be the largest index appearing in any barred multi-index of η. Group the terms uniquely as η=dzˉk∧τ+θ, absorbing the permutation signs into τ, so that neither τ nor θ contains a barred differential with index at least k. Here τ has type (p,q−1) and θ has type (p,q).

2.1F1F2step 1.1givenalgebra

The product rule [F2] gives 0=∂ˉη=−dzˉk∧∂ˉτ+∂ˉθ. For each ℓ>k, the coefficient terms containing both dzˉk and dzˉℓ can only come from −dzˉk∧∂ˉτ: the form θ has no barred factor with index at least k, so ∂ˉθ has no term containing both indices. Uniqueness of the wedge expansion [F1] therefore gives ∂zˉℓτ=0 for every ℓ>k, coefficientwise.

3.1F1F4F5step 2.1givenalgebra

Suppose the current residual form is smooth and closed on a working polydisc Q=∏Ej containing P′, and its largest barred index is k. In the descending process, the kth factor has not yet been shrunk, so Ek=Dk and Dk′‾⋐Ek. Apply the same local operator Tk from [F4] to each of the finitely many coefficient functions of τ in the unique expansion [F1]. It produces a smooth form ψk=Tkτ on a working polydisc Q′ that still contains P′, with ∂zˉkψk=τ. Since every coefficient of τ has zero zˉℓ derivative for ℓ>k by step 2.1, [F4] preserves those equations for ψk. The full AC premise needed for [F4] is part of the given hypothesis by [F5].

4.1F1F3step 3.1givenalgebra

By the coefficient formula [F1], ∂ˉψk=dzˉk∧τ+δk, where every barred index in δk is less than k: the kth derivative supplies the displayed first term, derivatives with index greater than k vanish by step 3.1, and the remaining derivatives have index less than k. Set ηk−1:=η−∂ˉψk=θ−δk. It has type (p,q) and contains only barred indices less than k. It remains closed, since ∂ˉηk−1=∂ˉη−∂ˉ2ψk=0 by [F3].

5.1F1F4F5step 1.1step 2.1step 3.1step 4.1givenalgebra

Repeat steps 1.1–3.1 on each nonzero residual, in descending order of the largest barred index. At each stage the local transform shrinks only the coordinate currently being processed and its output domain still contains P′, so all later residuals and the previously constructed primitives restrict to a common neighborhood of P′. If no barred factor occurs at index k, skip that transform and retain the current domain. After index 1 is removed, the residual has barred degree q>0 but no barred basis factor; the unique expansion [F1] forces it to be zero. There are at most n transforms.

6.1step 3.1step 4.1step 5.1givenalgebra∎

Let ψ be the sum of the finitely many forms ψk constructed by the repeated step 3.1 procedure in step 5.1, restricted to P′. The successive residual identities of step 4.1 telescope, and the final residual is zero by step 5.1; hence ∂ˉψ=η∣P′. Each summand is smooth on a neighborhood of P′, so ψ is smooth there and has type (p,q−1).

Depends on

Used by

Dependency tree · two levels

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Sources