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Positive-degree Dolbeault cohomology vanishes on polydiscs

Statement

Assume the full axiom of choice. Let n≥1 and let P=∏j=1nDj⊆Cn, where each Dj is a nonempty open disc of finite positive radius or is C. For integers 0≤p≤n and 1≤q≤n, every smooth η∈Ωp,q(P) with ∂ˉη=0 is ∂ˉ-exact: there is a smooth ω∈Ωp,q−1(P) such that ∂ˉω=η. Consequently, H∂ˉp,q(P)=0.

Facts & Assumptions

Given: Full AC; n≥1; P=∏j=1nDj with each factor a nonempty finite-radius open disc or C; integers 0≤p≤n and 1≤q≤n; and a smooth ∂ˉ-closed η∈Ωp,q(P).

[F1]

Smooth complex forms have a unique finite expansion in the basis dzI∧dzˉJ, with 0≤p,q≤n, and ∂ˉ is given coefficientwise by the Wirtinger derivatives (Bigraded complex forms and the Dolbeault operators).

[F2]

Under full AC, a smooth closed (p,q) form on a finite polydisc has a smooth (p,q−1) primitive on every coordinate polydisc whose closed coordinate discs are compactly contained in the source (The local Dolbeault lemma on nested polydiscs).

[F3]
[F4]

H∂ˉp,q(P) is the quotient of closed (p,q) forms by exact (p,q) forms (Dolbeault cohomology of a domain).

[F5]

Full AC means that every family of nonempty sets has a choice function (The Axiom of Choice).

[F6]

If K is compact in an open set W of a smooth manifold, there is a smooth function equal to 1 on a neighborhood of K whose support lies in W (A manifold bump for a compact set inside an open set).

[F7]

For a C1 function, the several-variable Cauchy–Riemann system is equivalent to complex differentiability at every point (For C1 functions, holomorphy, complex linearity of the real derivative, and the Cauchy–Riemann system agree).

[F8]

A function is holomorphic on an open set when it is complex differentiable at every point (Holomorphic functions on an open subset of Cm).

[F9]

A holomorphic function of several variables is continuous and separately holomorphic (A holomorphic function of several variables is continuous and separately holomorphic).

[F10]

A continuous separately holomorphic function on a polydisc has a power series that converges uniformly on every strictly smaller closed polydisc (A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc).

[F11]

A locally uniform limit of holomorphic functions on an open set is holomorphic there (Locally uniform limits of holomorphic functions are holomorphic, with locally uniform convergence of all derivatives).

[F13]

The support of a smooth form is the closure of its nonzero locus (Compact support of a differential form).

[F14]

In Cn, a subset is compact exactly when it is closed and bounded (Complex m-space and its real coordinate dictionary).

[F15]

Open and closed polydiscs are defined coordinatewise by strict and non-strict radius inequalities (Balls, polydiscs and the distinguished boundary in Cm).

[F16]

∂ˉ obeys the graded product rule (The d, partial and dbar identities).

Proof

technique · exhaustion and gluing
1.1F2F14F15givenconstruct

If η=0, take ω=0. Otherwise, write each finite-radius factor as D(aj,Rj) and set rj,k=(1−2−k)Rj; for each factor equal to C, use center aj=0 and radius rj,k=k. Let Pk=∏j=1nD(aj,rj,k). The sequence is increasing, ⋃kPk=P, and Pk‾⊂Pk+1 by [F15]. Each Pk‾ is closed and bounded in Cn, hence compact by [F14]. Thus every successive pair satisfies the compact-containment hypothesis of [F2].

1.2F2givenalgebrachoose

Suppose first that q>1. By [F2], choose a primitive ω1 on P3 using η on P4. Inductively suppose ωk is a smooth (p,q−1) form on Pk+2 with ∂ˉωk=η. By [F2], choose another primitive σ on Pk+3 using η on Pk+4. The difference d=ωk−σ on Pk+2 is a closed (p,q−1) form; because q−1≥1, [F2] gives a (p,q−2) form v on Pk+1 with ∂ˉv=d there.

2.1F3F5F6F13F16step 1.2givenalgebrachoose

Since Pk‾ is compact and contained in Pk+1, apply [F6] to obtain a smooth χ equal to 1 near Pk‾ with supp⁡χ⊂Pk+1. The support is closed by [F13]. Extend χv by zero outside Pk+1; near each boundary point of Pk+1 the closed support is absent, so this extension is smooth. Define ωk+1=σ+∂ˉ(χv) on Pk+3. By [F3], ∂ˉ2=0, so ∂ˉωk+1=∂ˉσ=η. On Pk, χ=1 on a neighborhood, so the product rule [F16] gives ∂ˉ(χv)=∂ˉv=d and ωk+1=ωk. Full AC [F5] supplies choices for the successive nonempty sets of local primitives and corrections at every finite stage.

2.2F1F2F5F7F8F9F10step 1.1givenalgebrachoose

Now suppose q=1. Use [F2] to choose ω1 on P3 with ∂ˉω1=η on P3. Given ωk on Pk+2, choose σ on Pk+3 with ∂ˉσ=η. On Pk+2, δ=σ−ωk is a closed (p,0) form. In its unique expansion δ=∑∣I∣=pδIdzI, [F1] and ∂ˉδ=0 imply ∂zˉjδI=0 for every I,j. Each coefficient is smooth, so [F7] and [F8] make it holomorphic; [F9] then makes it continuous and separately holomorphic. Apply [F10] to each of the finitely many coefficients on Pk+2. Since Pk‾⊂Pk+2, their Taylor polynomials can be chosen with maximum coefficient error less than 2−k on Pk‾. Let Qk be the resulting holomorphic polynomial (p,0) form and set ωk+1=σ−Qk on Pk+3. Then ∂ˉωk+1=η and every coefficient of ωk+1−ωk has absolute value below 2−k on Pk‾. Full AC [F5] supplies choices throughout this countable recursion.

3.1step 2.1givenalgebra

The exact agreement in step 2.1 defines a smooth form ω on P by ω∣Pk=ωk∣Pk. The sets Pk cover P and the definitions agree on each nested overlap. Locally ω equals a local primitive ωk, so ∂ˉω=η on all of P.

3.2F7F11F12step 2.2givenalgebra

For any compact K⊂P, the increasing open cover {Pk} has a finite subcover, so K⊂Pℓ for some ℓ. If m>k≥ℓ, the coefficient error estimate in step 2.2 gives ∥ωm−ωk∥K,∞≤∑j=km−12−j<21−k, where the norm is the maximum over the finitely many (p,0) coefficients and K. Thus the coefficients converge locally uniformly on P to those of a form ω. For each fixed ℓ, every coefficient of ωm−ωℓ is holomorphic on Pℓ for m≥ℓ, by the closed (p,0) argument in step 2.2. Their locally uniform limit is holomorphic on Pℓ by [F11], and is smooth by [F12]. By [F7], this holomorphic difference has zero ∂ˉ. Since ∂ˉωℓ=η, it follows that ω is smooth and ∂ˉω=η on every Pℓ, hence on P.

4.1F4step 3.1step 3.2givenalgebra∎

Both cases produce a smooth ∂ˉ-primitive for every closed (p,q) form on P. Therefore every element of the numerator in [F4] belongs to its exact-form denominator, and the quotient is the zero vector space.

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