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A holomorphic function of several variables is continuous and separately holomorphic

Statement

Let UCm be open and let f:UC be holomorphic (Holomorphic functions on an open subset of Cm). Then f is continuous on U and separately holomorphic on U (Separately holomorphic functions). Moreover, for aU and k<m the slice fa,k is complex differentiable at ak with derivative Df(a)ek, and

Df(a)ek=zkf(a),Df(a)h=k<m(zkf(a))hk.

Facts & Assumptions

Given: An open UCm and a holomorphic f:UC; Cm is read through Complex m-space and its real coordinate dictionary.

[L1]

f is complex differentiable at a when there is a C-linear L with f(a+h)=f(a)+L(h)+r(h) and r(h)/h0; that L is unique and written Df(a) (Holomorphic functions on an open subset of Cm).

[L2]

f is separately holomorphic when every slice fa,k is holomorphic on the open set Ua,k in the one-variable sense (Separately holomorphic functions, Complex differentiability at a point, the complex derivative, holomorphic functions, and entire functions).

[L3]

An R-linear T:CmC has a unique representation T(h)=k<mckhk+k<mdkhk, and T is C-linear exactly when every dk=0; for T=Df(a) at a point of real total differentiability, ck=zkf(a) and dk=zˉkf(a) (A real-linear functional on Cm is complex linear exactly when its antiholomorphic part vanishes, Wirtinger operators in Cm).

[L4]

For every linear L:RmRn there is K0 with Lh2Kh2 for every h (Every Euclidean linear map has a unique matrix and satisfies Lh2Kh2 for some K0).

[L5]

A complex differentiable function of one variable is continuous (Complex differentiability at a point implies continuity there).

[L7]

zw=zw and z+wz+w (Conjugation is an involutive real-field automorphism, zz=z2, and modulus is definite, multiplicative, and subadditive); finite sums are additive, scale and are monotone in their terms (Laws of finite sums and finite products).

[L8]

Continuity of a map into Rn from a subset of a metric space is the usual εδ condition with the Euclidean norm (Vector-valued functions f:ARm, their limits and continuity, with the dictionary to the metric notions).

Proof

technique · direct
1.1

Fix aU and write L=Df(a) as in [L1]. Since L is C-linear it is in particular R-linear, so [L4] read through the dictionary gives K0 with L(h)Kh for every h; alternatively [L3] and [L6] give L(h)=k<mckhk with ck=L(ek), and [L7] bounds L(h) by (k<mck)h because hkh.

givenL1L3L4L6L7
1.2

The remainder satisfies r(h)/h0 by [L1], so there is δ>0 with r(h)h whenever 0<h<δ and a+hU.

givenL1
1.3

Fix k<m, let aU and let ζUa,k. The point a obtained from a by replacing its kth coordinate by ζ lies in U and agrees with a off the kth coordinate, so Ua,k=Ua,k and fa,k=fa,k.

givenL2
2.1

Combining steps 1.1 and 1.2, f(a+h)f(a)L(h)+r(h)(K+1)h for such h, which tends to 0 with h; by [L8] this is continuity of f at a, and aU was arbitrary.

step 1.1step 1.2L7L8
2.2

With a as in step 1.3 and h=(ξζ)ek for ξ near ζ, [L1] and [L6] give fa,k(ξ)fa,k(ζ)=Df(a)ek(ξζ)+r(h), and h=ξζ by the dictionary, so r(h)/ξζ0. Hence fa,k is complex differentiable at ζ with derivative Df(a)ek; as ζUa,k was arbitrary, the slice is holomorphic on Ua,k and f is separately holomorphic by [L2].

step 1.3L1L2L6
3.1

By [L3] applied to the C-linear Df(a), every dk vanishes and Df(a)h=k<mckhk with ck=Df(a)ek=zkf(a); step 2.2 at ζ=ak identifies that number with the derivative of the slice, and [L5] confirms the slice is continuous, consistently with step 2.1.

step 2.1step 2.2L3L5L6

Depends on

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