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Sums, products and nonvanishing quotients of holomorphic functions are holomorphic

Statement

Let m1, let UCm be open and let f,g:UC be holomorphic. Then λf+μg is holomorphic on U for all λ,μC, fg is holomorphic on U, and f/g is holomorphic on the open set {zU:g(z)0}, with

D(λf+μg)(a)=λDf(a)+μDg(a),D(fg)(a)=f(a)Dg(a)+g(a)Df(a), D(f/g)(a)=g(a)Df(a)f(a)Dg(a)g(a)2(g(a)0),

and correspondingly zk(fg)=fzkg+gzkf and zk(f/g)=(gzkffzkg)/g2 for each k<m. In particular the holomorphic functions on U form a commutative ring under pointwise operations, containing the constants.

Facts & Assumptions

Given: An open UCm and holomorphic f,g:UC; Cm is read through Complex m-space and its real coordinate dictionary.

[L1]

f is complex differentiable at a when there is a C-linear L with f(a+h)=f(a)+L(h)+r(h) and r(h)/h0; L is unique and written Df(a) (Holomorphic functions on an open subset of Cm).

[L2]

A holomorphic function of several variables is continuous, and Df(a)h=k<m(zkf(a))hk (A holomorphic function of several variables is continuous and separately holomorphic).

[L3]

A map T(h)=k<mckhk is C-linear, and for a differentiable f the coefficients are zkf (A real-linear functional on Cm is complex linear exactly when its antiholomorphic part vanishes, Wirtinger operators in Cm).

[L4]

For every linear L:RmRn there is K0 with Lh2Kh2 for every h (Every Euclidean linear map has a unique matrix and satisfies Lh2Kh2 for some K0).

[L5]

Linear combinations, products and nonvanishing quotients of complex numbers obey the field laws (C=R[x]/(x2+1) is a field, every element is uniquely a+bi, and every nonzero element has inverse (abi)/(a2+b2)), and the one-variable derivative rules take the displayed forms (Linearity, product, reciprocal, and quotient rules for complex derivatives).

[L7]

zw=zw and z+wz+w (Conjugation is an involutive real-field automorphism, zz=z2, and modulus is definite, multiplicative, and subadditive).

Proof

technique · direct
1.1

Fix aU and write f(a+h)=f(a)+Df(a)h+rf(h) and g(a+h)=g(a)+Dg(a)h+rg(h) as in [L1], with rf(h),rg(h)=o(h); by [L4] read through the dictionary there is K0 with Df(a)hKh and Dg(a)hKh.

givenL1L4
2.1

For λ,μC the map hλDf(a)h+μDg(a)h is C-linear by [L3] and [L8], and the remainder of λf+μg at a is λrf(h)+μrg(h), which is o(h) by [L7]; so [L1] makes λf+μg complex differentiable at a with the stated differential.

step 1.1L1L3L7L8
2.2

Multiplying the two expansions of step 1.1 and collecting, f(a+h)g(a+h)=f(a)g(a)+(f(a)Dg(a)h+g(a)Df(a)h)+ϱ(h), where ϱ(h)=Df(a)hDg(a)h+(f(a)+Df(a)h)rg(h)+(g(a)+Dg(a)h+rg(h))rf(h). By step 1.1 and [L7] the first term is at most K2h2 and the others are bounded quantities times o(h), so ϱ(h)=o(h); the first-order part is C-linear by [L3], so [L1] gives the product rule.

step 1.1L1L3L5L7
2.3

Suppose g(a)0. By [L2] the function g is continuous, so [L6] gives a ball B about a inside U on which gg(a)/2>0; in particular {zU:g(z)0} is open by [L6]. On B write 1g(a+h)1g(a)=g(a)g(a+h)g(a)g(a+h)=Dg(a)hrg(h)g(a)g(a+h); using g(a+h)g(a) this equals Dg(a)hg(a)2+o(h) by step 1.1 and [L7]. So 1/g is complex differentiable at a with differential hDg(a)h/g(a)2, which is C-linear by [L3].

step 1.1L1L2L3L5L6L7
3.1

Combining steps 2.2 and 2.3 gives the quotient rule for f/g at every point where g does not vanish, and reading each differential at h=ek with [L2], [L3] and [L8] gives the displayed formulas for zk.

step 2.2step 2.3L2L3L5L8
4.1

Steps 2.1 and 2.2 make the holomorphic functions on U closed under pointwise addition and multiplication; those operations are commutative, associative and distributive because the values lie in the field C ([L5]), and every constant function is holomorphic with zero differential by [L1]. So the holomorphic functions on U form a commutative ring containing the constants.

step 2.1step 2.2L1L5

Depends on

Used by

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