Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every Euclidean linear map has a unique matrix and satisfies ∥Lh∥2≤K∥h∥2 for some K≥0

Statement

For every linear L:Rm→Rn there is a unique matrix A=(aij)i<n,j<m such that (Lh)i=∑j<maijhj. Moreover there is K≥0 with ∥Lh∥2≤K∥h∥2 for every h.

Facts & Assumptions

Given: A Euclidean linear map L:Rm→Rn.

[L1]
[L2]

The Euclidean norm of x is ∥x∥2=∑i<nxi2, and it is a norm (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

Proof

technique · direct
1.1

Put aij:=(Lej)i. By [L1] and linearity, Lh=L(∑j<mhjej)=∑j<mhjLej, so (Lh)i=∑j<maijhj.

L1L2
2.1

The columns Lej determine every value in step 1.1, and evaluating the displayed formula at ej shows that every representing matrix has exactly these entries; thus the matrix is unique.

step 1.1L2algebra
3.1

Let K=(∑i<n,j<maij2)1/2. Cauchy--Schwarz [L3] in each row and summing gives ∥Lh∥22≤K2∥h∥22, hence ∥Lh∥2≤K∥h∥2.

step 1.1step 2.1L3∎

Depends on

Used by

Dependency tree · two levels

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Sources