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Osgood's lemma: continuous and separately holomorphic implies holomorphic
Statement
Let , let be open and let be continuous and separately holomorphic (Separately holomorphic functions). Then is holomorphic on (Holomorphic functions on an open subset of ).
Consequently, for a continuous on an open the following three conditions are equivalent: is holomorphic; is separately holomorphic; every point of has a polydisc neighbourhood on which is the sum of an absolutely convergent multi-indexed power series.
Facts & Assumptions
Given: An open and a continuous separately holomorphic ; is read through Complex -space and its real coordinate dictionary.
For continuous and separately holomorphic on and a polyradius with , the iterated-integral coefficients satisfy with , and on , absolutely and uniformly on every with (A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc).
If for every , then converges absolutely on and its sum is holomorphic there (An absolutely convergent multi-indexed power series is holomorphic and differentiates termwise).
A holomorphic function of several variables is continuous and separately holomorphic (A holomorphic function of several variables is continuous and separately holomorphic).
Holomorphic on means complex differentiable at every point of (Holomorphic functions on an open subset of ), and separate holomorphy is a condition on the slices through each point (Separately holomorphic functions).
is defined coordinatewise by (Balls, polydiscs and the distinguished boundary in ), and a multi-indexed power series and its absolute convergence are those of Multi-indexed power series in and their absolute convergence.
A set is open exactly when each of its points admits a ball inside it, and (The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement, Open ball, closed ball and sphere in a metric space).
Proof
Fix . By [L6] there is with ; put for every . If then by [L5] and the dictionary, so .
The restriction of to is continuous, and it is separately holomorphic there: for and the slice domain inside is an open subset of the slice domain inside , on which the slice is holomorphic by hypothesis, and a restriction of a holomorphic function of one variable to an open subset is holomorphic.
Put , so . By [L1] applied on there are coefficients with and for every .
By [L2] the sum of that series is holomorphic on ; by step 2.1 it is there, so is complex differentiable at every point of , in particular at . Since was arbitrary, [L4] makes holomorphic on .
For the equivalence, let be continuous on the open . If is holomorphic then it is separately holomorphic by [L3]; if it is separately holomorphic then step 2.1 gives the local power-series representation and step 3.1 gives holomorphy; and if it is locally such a sum then [L2] makes it holomorphic on a polydisc about each point, hence on by [L4]. So the three conditions are equivalent.
Depends on
- A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc
- An absolutely convergent multi-indexed power series is holomorphic and differentiates termwise
- A holomorphic function of several variables is continuous and separately holomorphic
- Holomorphic functions on an open subset of $\mathbb{C}^m$
- Separately holomorphic functions
- Balls, polydiscs and the distinguished boundary in $\mathbb{C}^m$
- Multi-indexed power series in $\mathbb{C}^m$ and their absolute convergence
- The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement
- Open ball, closed ball and sphere in a metric space
- Conjugation is an involutive real-field automorphism, $z\overline z=|z|^2$, and modulus is definite, multiplicative, and subadditive
- Complex $m$-space and its real coordinate dictionary
Used by
- Holomorphic functions of several variables are smooth and their complex derivatives are holomorphic Corollary
- Conventions on this page, and what the several-variable identity theorem does not say Remark
- Why local boundedness gives joint continuity here and nothing like it holds in the real case Remark
- Locally bounded and separately holomorphic implies holomorphic Theorem
- Locally uniform limits of holomorphic functions are holomorphic, with locally uniform convergence of all derivatives Theorem
Dependency tree · two levels
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Sources
- H. P. Boas, Lecture Notes on Multidimensional Complex Analysis, Ch. 2 (standard reference, not scraped)
- M. Jabbari, Notes for Analysis and Geometry of Several Complex Variables, §3.1 (standard reference, not scraped)