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Osgood's lemma: continuous and separately holomorphic implies holomorphic

Statement

Let m1, let UCm be open and let f:UC be continuous and separately holomorphic (Separately holomorphic functions). Then f is holomorphic on U (Holomorphic functions on an open subset of Cm).

Consequently, for a continuous f on an open U the following three conditions are equivalent: f is holomorphic; f is separately holomorphic; every point of U has a polydisc neighbourhood on which f is the sum of an absolutely convergent multi-indexed power series.

Facts & Assumptions

Given: An open UCm and a continuous separately holomorphic f:UC; Cm is read through Complex m-space and its real coordinate dictionary.

[L1]

For f continuous and separately holomorphic on Δρ(a) and a polyradius r with rk<ρk, the iterated-integral coefficients satisfy cαMk<mrkαk with M=supΓr(a)f, and f(z)=αcα(za)α on Δr(a), absolutely and uniformly on every Δθr(a) with θ<1 (A continuous separately holomorphic function is the sum of an absolutely convergent power series with Cauchy-integral coefficients on every smaller polydisc).

[L2]

If cαMk<mrkαk for every α, then αcα(za)α converges absolutely on Δr(a) and its sum is holomorphic there (An absolutely convergent multi-indexed power series is holomorphic and differentiates termwise).

[L3]

A holomorphic function of several variables is continuous and separately holomorphic (A holomorphic function of several variables is continuous and separately holomorphic).

[L4]

Holomorphic on U means complex differentiable at every point of U (Holomorphic functions on an open subset of Cm), and separate holomorphy is a condition on the slices through each point (Separately holomorphic functions).

[L5]

Δr(a) is defined coordinatewise by zkak<rk (Balls, polydiscs and the distinguished boundary in Cm), and a multi-indexed power series and its absolute convergence are those of Multi-indexed power series in Cm and their absolute convergence.

[L6]

A set is open exactly when each of its points admits a ball inside it, and B(x,ε)={y:d(x,y)<ε} (The metric topology: a set is open when every one of its points has a ball around it inside the set; closed means open complement, Open ball, closed ball and sphere in a metric space).

[L7]

zw=zw and z+wz+w (Conjugation is an involutive real-field automorphism, zz=z2, and modulus is definite, multiplicative, and subadditive).

Proof

technique · direct
1.1

Fix aU. By [L6] there is ε>0 with B(a,ε)U; put ρk=ε/(2m) for every k<m. If zΔρ(a) then za2=k<mzkak2<mρ02=ε2/4 by [L5] and the dictionary, so Δρ(a)B(a,ε)U.

givenL5L6L7
1.2

The restriction of f to Δρ(a) is continuous, and it is separately holomorphic there: for bΔρ(a) and k<m the slice domain inside Δρ(a) is an open subset of the slice domain inside U, on which the slice is holomorphic by hypothesis, and a restriction of a holomorphic function of one variable to an open subset is holomorphic.

givenL4L5
2.1

Put rk=ρk/2, so rk<ρk. By [L1] applied on Δρ(a) there are coefficients cα with cαMk<mrkαk and f(z)=αcα(za)α for every zΔr(a).

step 1.1step 1.2L1L5
3.1

By [L2] the sum of that series is holomorphic on Δr(a); by step 2.1 it is f there, so f is complex differentiable at every point of Δr(a), in particular at a. Since aU was arbitrary, [L4] makes f holomorphic on U.

step 2.1L2L4
4.1

For the equivalence, let f be continuous on the open U. If f is holomorphic then it is separately holomorphic by [L3]; if it is separately holomorphic then step 2.1 gives the local power-series representation and step 3.1 gives holomorphy; and if it is locally such a sum then [L2] makes it holomorphic on a polydisc about each point, hence on U by [L4]. So the three conditions are equivalent.

step 2.1step 3.1L2L3L4

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