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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Every smooth oriented knot in S3 bounds a Seifert surface

Statement

Assume the Axiom of Countable Choice. Every smooth oriented knot K⊂S3 bounds a connected compact smooth oriented embedded surface F⊂S3 whose oriented boundary is K.

Facts & Assumptions

Given: ACω and a smooth oriented knot K⊂S3.

[F1]

A link in the standard S3 may be moved by an orientation-preserving ambient isotopy to lie in R3⊂S3. (Oriented links in the three-sphere and ambient isotopy)

[F2]

Under ACω, every oriented link contained in R3 has a dense set of regular projection directions. (Existence of regular projections)

[F3]

A regular oriented diagram of one knot component has a connected compact smooth oriented embedded disk-and-band realization with that oriented boundary. (Seifert disks and bands form an embedded oriented spanning surface)

[A1]

The Axiom of Countable Choice is the sequence principle stated in the item. (The Axiom of Countable Choice (ACω))

Proof

1.1givenF1F2A1choose

By [F1], move K by an orientation-preserving ambient isotopy into R3. Apply [F2] and [A1] to choose a regular projection direction. The resulting decorated projection is a finite regular oriented diagram D of a single knot.

2.1step 1.1F3construct∎

Apply [F3] to D to obtain a connected compact smooth oriented embedded surface with oriented boundary D. Pull the surface back by the inverse ambient isotopy from step 1.1; the inverse diffeomorphism preserves embeddedness, compactness, connectedness, orientation, and the boundary orientation, giving the required F for the original K.

Depends on

Used by

Dependency tree · two levels

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Sources