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Finite-dimensional laws of a Markov chain
Statement
Assume Choice. Let be a -chain with initial law . If and are bounded measurable real functions, then For , the integral is evaluation at . Taking gives the corresponding iterated-integral formula for the joint law of .
Facts & Assumptions
Given: Choice, a -chain with initial law , an increasing finite time list, and bounded measurable tests.
The initial law is , with the Dirac identity. (Initial distribution of a Markov chain)
The multistep identity is . (Chapman-Kolmogorov equations)
Conditional expectation satisfies the tower property. (Tower property of conditional expectation)
Probability measures agreeing on a generating pi-system agree on its sigma-algebra. (Dynkin's pi-lambda theorem)
Proof
Define backward, starting with , by [F2, F3] Every is bounded and measurable because kernel integration preserves measurability. Applying [F2] at time , multiplying by the bounded -measurable preceding product, and using [F3] removes and replaces it by . Repeating finitely many times gives
A final application of [F2] from time to time , followed by [F1, F2, step 1.1] integration against [F1], gives which expands to the displayed iterated integral. If , this same line is the whole calculation; if , the inner identity kernel simply evaluates . Choice is used in [F2]--[F3] and nowhere in the finite algebraic unwinding.
Put . The left side is the joint law's value on the rectangle [F4, step 1.1, step 2.1] , and the right side is the announced cylinder integral. These rectangles include empty factors and the full rectangle, form a pi-system, and generate the finite product sigma-algebra. By [F4] their values determine the joint law uniquely. Conversely, the stated joint law integrates every bounded product test by the same iterated-integration calculation, so the two displayed formulations are equivalent.
Depends on
Used by
Dependency tree · two levels
22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Durrett, Probability: Theory and Examples, Section 5.1 (standard reference, not scraped)