Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
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Finite-dimensional laws of a Markov chain

Statement

Assume Choice. Let X be a K-chain with initial law μ. If 0n0<<nr and f0,,fr are bounded measurable real functions, then Ej=0rfj(Xnj)=Eμ(dx)EKn0(x,dx0)f0(x0)EKn1n0(x0,dx1)f1(x1)EKnrnr1(xr1,dxr)fr(xr). For n0=0, the K0 integral is evaluation at x. Taking fj=1Aj gives the corresponding iterated-integral formula for the joint law of (Xn0,,Xnr).

Facts & Assumptions

Given: Choice, a K-chain with initial law μ, an increasing finite time list, and bounded measurable tests.

[F1]

The initial law is L(X0), with K0 the Dirac identity. (Initial distribution of a Markov chain)

[F2]

The multistep identity is E[f(Xm+n)Fm]=Knf(Xm). (Chapman-Kolmogorov equations)

[F3]

Conditional expectation satisfies the tower property. (Tower property of conditional expectation)

[F4]

Probability measures agreeing on a generating pi-system agree on its sigma-algebra. (Dynkin's pi-lambda theorem)

Proof

1.1

Define backward, starting with Gr=fr, by [F2, F3] Gj(x)=fj(x)Knj+1njGj+1(x),0j<r. Every Gj is bounded and measurable because kernel integration preserves measurability. Applying [F2] at time nr1, multiplying by the bounded Fnr1-measurable preceding product, and using [F3] removes fr(Xnr) and replaces it by Knrnr1fr(Xnr1). Repeating finitely many times gives Ej=0rfj(Xnj)=E[G0(Xn0)].

F2F3
2.1

A final application of [F2] from time 0 to time n0, followed by [F1, F2, step 1.1] integration against [F1], gives E[G0(Xn0)]=μ(dx)Kn0(x,dx0)G0(x0), which expands to the displayed iterated integral. If r=0, this same line is the whole calculation; if n0=0, the inner identity kernel simply evaluates G0(x). Choice is used in [F2]--[F3] and nowhere in the finite algebraic unwinding.

F1F2step 1.1
3.1

Put fj=1Aj. The left side is the joint law's value on the rectangle [F4, step 1.1, step 2.1] A0××Ar, and the right side is the announced cylinder integral. These rectangles include empty factors and the full rectangle, form a pi-system, and generate the finite product sigma-algebra. By [F4] their values determine the joint law uniquely. Conversely, the stated joint law integrates every bounded product test by the same iterated-integration calculation, so the two displayed formulations are equivalent.

F4step 1.1step 2.1

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