Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The first possible complex K-theory AHSS differential is integral Sq-three

Statement

Assume AC. In the complex topological K-theory Atiyah–Hirzebruch spectral sequence of Complex K-theory AHSS, the first two possible differentials are d2=0,d3=SqZ3=βZ Sq2 ρ2, with Bott-periodic translates of this formula on all even coefficient rows. Here ρ2 is reduction modulo two, Sq2 is the Steenrod square and βZ is the integral Bockstein of 0→Z→2Z→Z/2→0; the operation is defined on integral cohomology by SqZ3=βZSq2ρ2:Hn(X;Z)→Hn+3(X;Z).

Facts & Assumptions

[A1]

Assume AC. For a finite CW complex the K-AHSS has E2p,q=Hp(X;Z) for even q, E2p,q=0 for odd q, and dr:Erp,q→Erp+r,q−r+1 (Complex K-theory AHSS).

[A2]

Under the K-AHSS, for p≥1 the differential d3 is read from the relevant kp+3 Postnikov layer of the total-degree representing space kup+q; after Bott translation to a nonpositive coefficient row, this is the stable operation βZSq2ρ2 (KU representability and the skeletal–Postnikov d-three comparison, The first connective complex K-theory Postnikov invariant is integral Sq-three).

[A3]

Steenrod squares vanish above the degree: for x∈Hn(X;F2) one has Sqkx=0 when k>n, so in particular Sq2(ρ2y)=0 for y∈H0(X;Z) (Steenrod normalization, instability, suspension, and top square, Steenrod squares from cup-i).

[A4]

A finite CW complex has finitely many path components, each a connected finite CW complex with H0(Xa;Z)=Z. Naturality gives restriction maps of the K-AHSS along the component inclusions (Naturality and edge maps of the AHSS).

[A5]

Bott periodicity gives natural isomorphisms Kq(X)≅Kq−2(X) and identifies all even coefficient rows with the row K0(∗)=Z (Complex Bott periodicity).

Proof

technique · direct

Given: Assume AC, a finite CW complex X, and the K-AHSS of [A1].

1.1A1A5given

The differential d2 has bidegree (2,−1): it maps the even coefficient row q to the odd row q−1, which is zero by the coefficient computation; hence d2=0 and E3=E2.

1.2A1A4given

Let X=∐a=1mXa be the finite decomposition into connected components. On each Xa, every class of H0(Xa;Z)=Z is pulled back from the point, so naturality identifies its d3 with the pullback of d3 on the point; the latter has target H3(pt;Z)=0. For y∈H0(X;Z), naturality along Xa↪X therefore makes every restriction of d3y∈H3(X;Z) zero. Every singular simplex of a disjoint union lies in one component, so restriction gives an isomorphism of singular cochain complexes C∗(X;Z)≅∏a=1mC∗(Xa;Z) and hence an injective map H3(X;Z)→∏aH3(Xa;Z). Thus d3y=0 without assuming a componentwise decomposition of the entire AHSS.

1.3A2A5given

For p≥1 and any even coefficient row, the comparison and k-invariant lemmas identify d3 on E3p,q with βZSq2ρ2, transported along the Bott identification of the coefficient rows.

2.1A3step 1.2

On the p=0 row the operation βZSq2ρ2 also vanishes, since Sq2 is zero on classes of degree zero by instability; thus the formula d3=βZSq2ρ2 holds on the p=0 row as well.

3.1A5step 1.1step 1.3step 2.1

Combining steps 1.1, 1.3 and 2.1 gives d2=0 and d3=βZSq2ρ2 on every even coefficient row, with the Bott-periodic translates supplied by [A5]; the sign ambiguity of the long exact sequence convention is immaterial because the operation has order two.

4.1step 3.1∎

step 3.1 proves the asserted vanishing of d2 and the identification of d3 with SqZ3=βZSq2ρ2 on all even coefficient rows.

Source notes

Compare Ji, Proposition 3.12, printed p. 12, for the statement d3=Sq~3 and the description of the operation as the composite of reduction mod two, Sq2 and the integral Bockstein; the normalization of the operation is supplied by Adams, Proposition 16.6, printed pp. 391–393.

Depends on

Used by

Dependency tree · two levels

43 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources