Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-14
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Steenrod normalization, instability, suspension, and top square

Statement

For xHn(X;F2),

Sq0x=x,Sqkx=0 if k>n,Sqnx=xx.

The same assertions hold relatively. On reduced cohomology of based CW complexes, every square commutes with the standard cohomology suspension:

Sqk(σx)=σ(Sqkx).

Facts & Assumptions

Given: A mod-two class x=[a] of degree n and an integer k; for the suspension calculation put j=nk.

[F1]

Squares are independent of the coherently carried higher-diagonal system (Steenrod squares are well-defined and natural).

[F2]

For 0kn, Sqk[a] is represented by anka, and its outside-range values are zero (Steenrod squares from cup-i).

[F3]

Cup-0 is the ordinary cup product, negative cup indices are zero, and the products restrict to relative cochains (Higher cup-i products).

[F4]

The mod-two cup-i coboundary formula has the two transposed cup-(i1) terms (Cup-i coboundary identity).

[F5]

In the pair sequence the connector sends [a] to [δa~] for any cochain extension a~ (Long exact sequence of a pair in singular cohomology).

[F6]

For a well-pointed based space (X,x0), use the reduced cone CX=(X×I)/(X×{1}{x0}×I) and define its reduced suspension as the quotient ΣX=CX/X, where X is the height-zero cone base.

[F7]

Squares are natural for maps of spaces and pairs (Steenrod squares are well-defined and natural).

[F8]

Homotopic maps induce the same singular-cohomology map for every abelian coefficient group (Homotopic maps induce equal maps in singular cohomology).

[F9]

Singular cohomology satisfies excision for a closed set contained in the interior of the relative subspace (Excision for singular cohomology).

Proof

Proof technique: an explicit normalized cup-i system and a cone-pair cochain calculation.

1.1

First prove Sq0=id. [F1, F2] Use the standard face-formula system of Medina--Mardones, Definition 7 and Theorem 10 (printed pages 8--9). On an m-simplex s it is

Distd(s)=UdU0sdU1s,

where U={u1<<umi}{0,,m} and U0,U1 partition U according to the parity of urr. Its proof uses only the face identities, so the same formula applies to the simplicial set of singular simplices, including its degenerate simplices. Example 8 identifies D0std with Alexander--Whitney, while for i=m the only index set is U=, giving

Dmstd(s)=ss.

Thus, for an n-cochain a and every singular n-simplex s, (ana)(s)=a(s)2=a(s) in F2. By [F2] this cochain represents Sq0[a], and [F1] permits the computation with this normalized system. Hence Sq0x=x.

1.2

Instability and the top square follow at the two definition endpoints. [F2, F3] If k>n, [F2] declares Sqkx=0. If k=n, its representing cochain is a0a, which is the ordinary cup product by [F3]. Therefore Sqnx=xx. The same argument uses the relative products when x is relative.

1.3

Represent the cone-pair connector without a choice. [F5, F6] Extend the cocycle a from the cone base XCX to a cochain b on CX by setting it to zero on every singular simplex not lying in X. Then c:=δb vanishes on chains in X and so is a relative cocycle in Cn+1(CX,X;F2). By [F5], [c]=[a]. This extension is a specified function, not an application of AC.

2.1

The connector commutes with every square. [F2, F3, F4, F5, step 1.3] For 0kn, set j=nk and define

b:=bj+1δb+bjb.

Because bX=a and (δb)X=0, its restriction is bX=aja, a representative of Sqk[a]. Applying [F4] twice and using δ2b=0 gives

δb=δbj+1δb+bjδb+δbjb+δbjb+bjδb+bj1b+bj1b=δbj+1δb.

The last cochain is the relative representative for Sqk[c], since c has degree n+1. Hence [F5] gives Sqk[a]=Sqk[a]. There is one further endpoint: if k=n+1, then Sqn+1[a]=0, while b0δb restricts to zero on X and

δ(b0δb)=δb0δb

by the ordinary mod-two Leibniz rule, the i=0 case of [F4]. Thus the top square of [c] is also zero. For k<0 or k>n+1, both sides are zero by [F2]; negative cup indices in the preceding calculation are zero by [F3].

3.1

The cone-pair connector is the reduced suspension after the quotient comparison. [F5, F6, F7, F8, F9, step 2.1] Take a based CW complex. If its basepoint lies inside a positive-dimensional open cell, radially subdivide that characteristic disk there and keep the higher attaching maps; this finite refinement makes it a vertex without changing the based space. For every nonbasepoint n-cell of X, its product with the open height interval in [F6] gives an (n+1)-cell of CX; the height-zero cells form the copy of X, while X×{1} and the basepoint track collapse to one vertex. The product characteristic disks supply the attaching maps, and each has finite boundary-cell support because its X-cell does. Their quotient map-out test and the CW weak topology give the cone its CW structure, with X a closed subcomplex. The cellwise radial collar of this subcomplex gives an open neighborhood V that strongly deformation retracts onto X: extend the collar and its radial flow over each characteristic disk, and assemble the compatible extensions using the CW weak topology. Since XV is the entire collapsed fibre of q:CXΣX, V is saturated; hence q(V) is open and the flow descends to a retraction onto the quotient vertex.

The pair sequences and [F8] make H(V,X;F2) and H(q(V),{};F2) zero. Restriction of cochains gives short exact sequences for the triples (CX,V,X) and (ΣX,q(V),{}); zero-extension proves their surjectivity. Their long exact sequences therefore identify the relative groups for X and V, and for {} and q(V). Apply [F9] with removed sets X and {}, respectively. After removal the map q:CXΣX is a homeomorphism of the two remaining pairs, so the excision squares give an isomorphism q:H(ΣX,{};F2)H(CX,X;F2). Thus the standard reduced suspension is (q)1 followed by the cone-pair connector [F5]. The quotient maps are natural, and [F7] makes squares natural for them. Step 2.1 therefore yields Sqkσ=σSqk. Empty or one-point reduced groups, the zero class, degree zero, and degenerate singular simplices were all included above, and no choice principle was used. ∎

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources