Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-02
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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In a commutative ring, (S) consists of finite sums ∑risi, and (a)=Ra

Statement

In a commutative ring, (S) consists of finite sums ∑risi, and (a)=Ra.

The empty sum is included and equals 0.

Facts & Assumptions

Given: A commutative ring R and a subset S⊆R.

[L1]

(S) is the intersection of ideals containing S (The ideal generated by a subset and principal ideals).

[L2]

The ideal criterion uses subtraction and absorption (Ideal criteria and intersections of ideals).

[L3]

Multiplication in a commutative ring commutes (Commutative ring).

Proof

technique · direct
1.1

Let J be the finite sums ∑risi; it contains S and is closed under subtraction and multiplication by arbitrary ring elements.

L1L2L3givenalgebra
2.1

Thus J is an ideal containing S, while every ideal containing S contains each such finite sum.

step 1.1L1L2L3givenalgebra
3.1

Hence J=(S); taking S={a} gives (a)=Ra.

step 2.1∎

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources