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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-02
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The canonical bundle of a genus-one curve is trivial

Statement

Assume the Axiom of Choice as inherited from the duality suppliers. Let C be a smooth proper geometrically integral curve over a field k of genus g=1. Then ωC is isomorphic to OC, every canonical divisor is principal, and h0(C,ωC)=1. No rational point of C is needed.

Facts & Assumptions

Given: A field k; a smooth proper geometrically integral curve C over k of genus g=1; its canonical bundle ωC and a canonical divisor KC.

[F1]

For a canonical divisor on a smooth proper geometrically integral curve of genus g one has deg⁡k(KC)=2g−2; for g=1 therefore deg⁡k(KC)=0. (The canonical divisor has degree 2g - 2)

[F2]

The canonical sheaf has h0(C,ωC)=g and l(KC)=g for every canonical divisor; for g=1 therefore h0(C,ωC)=1 and l(KC)=1, so H0(C,ωC) is one-dimensional and nonzero. (The canonical bundle has exactly g independent sections, The Riemann-Roch dimension l(D))

[F3]

A degree-zero invertible sheaf with a nonzero global section is trivial: if L is invertible on C with deg⁡(L)=0 and H0(C,L)≠0, then L≅OC; equivalently, a nontrivial degree-zero invertible sheaf has no nonzero global section. (A degree-zero line bundle with a nonzero section is trivial)

[F4]

The canonical bundle is ωC=ΩC/k1, and for a nonzero rational differential ω with divisor KC=div⁡(ω) one has ωC≅OC(KC); the divisors of the nonzero rational differentials form a single linear equivalence class, so any two canonical divisors are linearly equivalent. (Canonical bundle and canonical divisors)

[F5]

An invertible sheaf on C is locally free of rank one; for the structure sheaf OC the global sections are the constants and l(0)=1, the degree of OC≅OC(0) being deg⁡k(0)=0. (Invertible sheaves, Degree divisor proper curve, The Riemann-Roch dimension l(D))

[F6]

The Axiom of Choice: every family of nonempty sets has a choice function. (The Axiom of Choice)

Proof

Proof technique: direct; combine deg⁡ωC=0 with h0(ωC)=1 and the triviality criterion for degree-zero line bundles.

1.1F1F2F4given

(Set-up.) By [F4] the canonical sheaf ωC=ΩC/k1 is invertible and ωC≅OC(KC) for the canonical divisor KC of any nonzero rational differential, and the canonical divisors form a single linear equivalence class; by [F1] one has deg⁡k(KC)=2g−2=0, and by [F2] one has h0(C,ωC)=l(KC)=g=1.

2.1F1step 1.1

The degree of the invertible sheaf ωC is computed by the degree of any associated divisor, so deg⁡(ωC)=deg⁡k(KC)=0 by step 1.1.

2.2F2step 1.1

By [F2] the space H0(C,ωC) has dimension one, hence is nonzero.

3.1F3step 2.1step 2.2

Since ωC is an invertible sheaf of degree zero with nonzero H0 by steps 2.1 and 2.2, the criterion [F3] gives ωC≅OC.

4.1F4F5step 1.1step 3.1

(Canonical divisors are principal.) By step 3.1 ωC is trivial, so a generator ω0∈H0(C,ωC), which exists because h0(C,ωC)=1 by step 1.1, is a nowhere-vanishing global section; under an isomorphism ωC≅OC from step 3.1 it corresponds to a nonzero global section of OC, and the divisor of a nonzero global section of an invertible sheaf is effective of degree deg⁡(ωC)=0 by [F5], hence is the zero divisor because the only effective divisor of degree zero on C is 0; thus the canonical divisor div⁡(ω0)=0 is principal. Since by [F4] every canonical divisor is linearly equivalent to this one, every canonical divisor is the divisor of a rational function, that is, principal.

5.1F6step 1.1step 3.1step 4.1∎

Assertions: ωC≅OC is step 3.1, h0(C,ωC)=1 is step 1.1 (in particular no rational point of C was used anywhere), and the principality of all canonical divisors is step 4.1; the Axiom of Choice [F6] is used exactly through the duality suppliers cited above.

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