Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The hom-assignment C(−,−):Cop×C→Set is a bifunctor

Statement

For every locally small category C, the hom-assignment

C(−,−):Cop×C⟶Set

of The covariant and contravariant hom-assignments and the hom-bifunctor of a locally small category is a functor. Its restrictions in the two variables are the contravariant and covariant hom-functors of The assignments C(a,−) and C(−,a) are functors to Set.

Facts & Assumptions

Given: A locally small category C; morphisms h:a′→a, k:a′′→a′, u:b→b′, and v:b′→b′′; and the category axioms of C.

[L1]

The one-variable assignments C(a,−) and C(−,a) are functors to Set (The assignments C(a,−) and C(−,a) are functors to Set).

[F1]

A morphism in a product category is a pair, and identities and composition are componentwise (Product category and its projection functors).

[F2]

The hom-assignment sends (h,u) to f↦u∘f∘h (The covariant and contravariant hom-assignments and the hom-bifunctor of a locally small category).

Proof

technique · direct
1.1

If f:a→b, then u∘f∘h:a′→b′, so [F2] defines a function C(a,b)→C(a′,b′).

givenF2
1.2

For every f:a→b, the identity pair acts by 1b∘f∘1a=f.

givenF1F2
1.3

Applying (h,u) and then (k,v) sends f to v∘(u∘f∘h)∘k=(v∘u)∘f∘(h∘k), which is the action of their componentwise composite in Cop×C.

givenF1F2
2.1

Steps 1.1--1.3 prove the functor laws, and fixing either variable recovers the postcomposition or precomposition action of [L1]; hence the hom-assignment is the asserted bifunctor.

step 1.1step 1.2step 1.3L1∎

Depends on

Used by

Cited to discharge well-definedness by The covariant and contravariant hom-assignments and the hom-bifunctor of a locally small category.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources