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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-30
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Inducing the trivial representation gives the permutation representation on G/H

Statement

Let G be a finite group and let H≤G. Inducing the trivial complex representation of H to G gives the permutation representation of G on the left coset set G/H.

Facts & Assumptions

Given: A finite group G, a subgroup H≤G, and the trivial complex representation 1H of H.

[F1]

The induced module consists of the functions f:G→C satisfying f(gh)=h−1⋅f(g), with G acting by (x⋅f)(g)=f(x−1g) (The induced R-linear G-module Ind⁡HGW as H-covariant functions on G).

[F2]

The left cosets of H are the subsets gH, and the permutation representation on a finite G-set has basis vectors indexed by that set (Left and right cosets gH and Hg of a subgroup, The trivial representation, the regular representation, and permutation representations from finite G-sets).

Proof

technique · direct
1.1F1given

In the trivial representation of H, every h∈H acts as the identity on C. So the covariance condition of [F1] becomes f(gh)=f(g) for all g∈G and h∈H. Therefore f is constant on each left coset gH.

2.1F2step 1.1construct

Define Φ:Ind⁡HG1H⟶C(G/H) by Φ(f)(gH):=f(g). Step 1.1 makes this well defined, and every function on G/H pulls back uniquely to an H-covariant function on G, so Φ is a linear bijection.

3.1F1F2step 2.1algebra

For x∈G, one has Φ(x⋅f)(gH)=(x⋅f)(g)=f(x−1g)=Φ(f)(x−1gH), which is exactly the left permutation action of G on the coset set G/H from [F2]. Hence Φ is G-equivariant.

4.1step 2.1step 3.1∎

The bijection of step 2.1 and the equivariance of step 3.1 identify Ind⁡HG1H with the permutation representation of G on G/H.

Depends on

Used by

Dependency tree · two levels

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Sources