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TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The interval Krawczyk certifier has the stated per-system guarantee

Statement

If Interval Krawczyk linear system certifier with explicit statuses returns existence-certified, every admitted system Ax=b has at least one solution in X. If it also returns unique-certified, each fixed admitted pair has exactly one solution in X. Inconclusive asserts neither existence nor singularity.

Facts & Assumptions

Given: The admitted matrix and right-hand-side families, box X, x0∈X, a supplied inverse witness S for R, and an existence-certified run.

[F1]

Outward interval operations enclose their exact expression ranges (Outward-rounded operations are inclusion-isotone and enclose DAG evaluations).

[F2]

Krawczyk set inclusion gives existence, and a defect norm below one gives uniqueness (Krawczyk inclusion gives solutions and contraction gives uniqueness).

[F3]

On an existence-certified return the admitted inputs satisfy RS=SR=I, and the algorithm checks that its outward Krawczyk enclosure lies in X; on a unique-certified return it also supplies an outward defect bound q<1 (Interval Krawczyk linear system certifier with explicit statuses).

Proof

1.1givenF1F2F3algebra

Since RS=SR=I, the supplied R is invertible. By [F1], the computed enclosing box contains every exact value of x0−R(Ax0−b)+(I−RA)(x−x0) for each admitted pair and each x∈X. Its successful inclusion in X therefore implies the set K∗(X) from [F2] is contained in X.

2.1givenF2F3step 1.1∎

Apply [F2] to each fixed pair to obtain a solution in X. If the run also reports unique-certified, [F3] supplies an outward row-sum bound with ∥I−RA∥∞,C≤q<1 for every admitted A, so the uniqueness clause of [F2] applies separately to every pair. If that strict bound is not returned, no uniqueness claim follows.

Depends on

Used by

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Sources