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Jordan's derangement theorem: every transitive action of a finite group on a finite set with more than one element has a nonidentity element with no fixed points
Statement
Let a finite group act transitively on a finite set with . Then some nonidentity is a derangement:
Facts & Assumptions
Given: A transitive action of a finite group on a finite set with .
A transitive action has exactly one orbit (Left group actions, transitive actions, and faithful actions).
The fixed-point set is (The fixed-point sets and of a group action).
Cauchy-Frobenius gives (Cauchy-Frobenius orbit counting: for a finite group action).
Finite cardinalities add over disjoint unions (The sum rule: a finite disjoint union is finite with and , and a sum over a finite index set splits along a partition, The cardinality of a finite set).
Finite sums over finite index sets are well-defined (The sum over a finite index set, and its product form).
Proof
By transitivity [L1], , so [L3] gives .
The identity fixes every point, so ; splitting its term from the finite sum gives .
Suppose, for contradiction, that every nonidentity fixes a point. Then every term in the remaining sum is at least , so step 1.2 gives , since .
This contradicts step 1.1. Therefore some has ; the identity fixes all of , so this is nonidentity.
Depends on
- Left group actions, transitive actions, and faithful actions
- The fixed-point sets $X^g$ and $X^G$ of a group action
- Cauchy-Frobenius orbit counting: $|G|\,|X/G|=\sum_{g\in G}|X^g|$ for a finite group action
- The cardinality $\lvert A\rvert$ of a finite set
- The sum rule: a finite disjoint union is finite with $\lvert A \cup B\rvert = \lvert A\rvert + \lvert B\rvert$ and $\lvert\bigcup_{i \in I} A_i\rvert = \sum_{i \in I}\lvert A_i\rvert$, and a sum over a finite index set splits along a partition
- The sum $\sum_{i \in S} a_i$ over a finite index set, and its product form
Used by
Nothing in the library uses this result yet.
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 76 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- K. Conrad, Group Actions, Theorem 6.6 (standard reference, not scraped)