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Kantorovich–Rubinstein duality on compact metric spaces under countable choice

Statement

Assume the Axiom of Countable Choice. Let (X,d) be a nonempty compact metric space, let μ,ν be countably additive Borel probability measures on X, and fix x0∈X. Define ΠX(μ,ν) to be the Borel probability measures γ on the product-topology space X×X satisfying γ(A×X)=μ(A) and γ(X×A)=ν(A) for every Borel set A⊆X, and define W1X(μ,ν)=inf⁡γ∈ΠX(μ,ν)∫X×Xd(x,y) dγ(x,y). Then ΠX(μ,ν) is nonempty and W1X(μ,ν)=sup⁡{∫Xf dμ−∫Xf dν: f:X→R, f(x0)=0, ∣f(x)−f(y)∣≤d(x,y) for all x,y∈X}.

Facts & Assumptions

Given: The Axiom of Countable Choice and the compact metric space and measures in the Statement.

[A1]

The Axiom of Countable Choice selects a member from each set in a countable family of nonempty sets. The Axiom of Countable Choice (ACω)

[F1]

Under the Axiom of Countable Choice, every compact metric space is second-countable. A compact metric space is second-countable under countable choice

[F2]

On a nonempty compact second-countable metric space, the Borel coupling set is nonempty and the 1-Wasserstein cost equals the supremum over basepoint-normalized 1-Lipschitz functions. Kantorovich–Rubinstein duality on compact second-countable metric spaces

Proof

technique · direct
1.1givenA1F1F2

By [A1] and [F1], the metric topology of X has an at-most-countable basis, so the hypotheses of [F2] hold. The countable-choice use is exactly the one recorded in [F1]; no other selection is needed.

2.1step 1.1F2∎

Apply [F2] to X,μ,ν and the fixed point x0. It gives ΠX(μ,ν)≠∅ and the displayed Kantorovich–Rubinstein equality.

Depends on

Used by

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Dependency tree · two levels

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Sources