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Borel product probabilities on compact metric spaces by sections

Statement

Let X,Y be nonempty compact metric spaces, let μ,ν be countably additive Borel probability measures on X,Y, and give X×Y its product topology. For every Borel set E⊆X×Y, its section Ex:={y∈Y:(x,y)∈E} is Borel in Y, and x↦ν(Ex) is Borel measurable. The formula λ(E):=∫Xν(Ex) dμ(x) defines a Borel probability measure on X×Y satisfying λ(A×B)=μ(A)ν(B) for every Borel A⊆X and B⊆Y. In particular its coordinate marginals are μ,ν.

Facts & Assumptions

Given: The compact metric spaces, probabilities, and product topology in the Statement.

[F2]

If an open set in Y×X contains K×{x} for compact K⊆Y, the tube lemma gives an open neighborhood V of x with K×V contained in that set. It uses an indexed family of all admissible pairs of neighborhoods and one finite subcover, without choice. Tube lemma: if K is a compact subset of a metric space X, Z is a topological space and N is open in X×Z with K×{z0}⊆N, then K×W⊆N for some open W∋z0

[F3]

Measures are continuous from below on increasing measurable sequences. Continuity from below for measures

[F4]

A lambda-system containing a pi-system contains its generated sigma-algebra. Dynkin's pi-lambda theorem

[F7]

Finite sums and real scalar multiples of real Borel measurable functions are Borel measurable, as are increasing pointwise limits of nonnegative Borel functions. Closure properties of measurable functions used by the integral

[F8]

A measure takes nonnegative values and is countably additive on disjoint measurable sets. Measures on sigma-algebras

Proof

technique · direct
1.1givenF1F3F6construct

For an open set G⊆Y with G≠Y, put Kn:={y:d(y,Y∖G)≥1/n} for integers n≥1. By [F1] these sets are closed and compact. They increase, lie in G, and exhaust G: if y∈G, some ball B(y,r) lies in G, so d(y,Y∖G)≥r>0 and y∈Kn for some n. If G=Y, use Kn=Y. Thus [F3] gives ν(G)=sup⁡nν(Kn) for a specified compact exhaustion of each open G, including G=∅.

2.1step 1.1F2F6F8choose

Let U⊆X×Y be open. The map y↦(x,y) is continuous for fixed x, so each Ux is open. Put hU(x)=ν(Ux). If hU(x)>a for a≥0, step 1.1 provides one compact K⊆Ux with ν(K)>a. The coordinate interchange S:Y×X→X×Y, S(y,z)=(z,y), is a homeomorphism: it and its inverse take basic open rectangles to basic open rectangles by [F6]. Thus S−1(U) is open and contains K×{x}. Apply [F2] in Y×X to obtain an open neighborhood V of x with K×V⊆S−1(U), or equivalently V×K⊆U. For every z∈V, K⊆Uz and hU(z)=ν(Uz). The set K is one of the closed sets in the exhaustion from step 1.1, and Uz is open, so K and Uz∖K are Borel by [F6]. Their disjoint union is Uz; apply countable additivity to the disjoint sequence K,Uz∖K,∅,… [F8]. Nonnegativity of ν [F8] then gives hU(z)=ν(K)+ν(Uz∖K)≥ν(K)>a. Consequently {hU>a} is open for every real a (for a<0 it is all of X). Hence hU is lower semicontinuous and Borel: the inverse images of real rays (a,+∞) are open, and these rays generate the real Borel sigma-algebra, as their rational subfamily generates all open intervals by countable unions and complements.

3.1step 2.1F4F6F7construct

Every Borel E⊆X×Y has Borel sections because the continuous map y↦(x,y) has inverse image Ex. Let D be the family of Borel E for which hE(x):=ν(Ex) is Borel. It contains X×Y, with h=1. If E∈D, then hEc=1−hE is Borel by [F7]. For disjoint En∈D, countable additivity of ν gives h⋃nEn=∑nhEn, an increasing limit of Borel partial sums and therefore Borel by [F7]. Thus D is a lambda-system. All open sets belong to it by step 2.1; the open sets form a pi-system generating B(X×Y). By [F4], D=B(X×Y).

4.1step 3.1F5construct

Define λ(E)=∫hE dμ, which is meaningful and lies in [0,1] by step 3.1 and [F5]. It has λ(∅)=0 and λ(X×Y)=1. For disjoint Borel En, step 3.1 gives h⋃nEn=lim⁡N∑n=1NhEn increasingly. Finite additivity and monotone convergence [F5] yield λ(⋃nEn)=lim⁡N∑n=1Nλ(En)=∑nλ(En). Hence λ is a countably additive Borel probability.

5.1step 4.1F5F6∎

For Borel A⊆X,B⊆Y, the rectangle A×B is Borel as the intersection of the two coordinate inverse images. Its section measure is hA×B(x)=1A(x)ν(B). The simple-integral formula [F5] gives λ(A×B)=μ(A)ν(B). Taking B=Y or A=X proves the marginal identities.

Remarks

This construction works on the full Borel sigma-algebra of the product topology. It neither asserts nor uses equality with the sigma-algebra generated by Borel rectangles. It requires no simultaneous selection of finite nets. The integral convergence is over specified sequences, and the compact exhaustion in step 1.1 is given by a formula. A general optimal-coupling attainment theorem is not part of this lemma.

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