Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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Agreement of the integral and L2 transforms

Statement

Assume countable choice. If fL1L2, its bounded continuous integral transform f^ represents F2f almost everywhere.

Facts & Assumptions

[F1]

Plancherel is a continuous extension of the Schwartz transform (Plancherel theorem).

[F2]

The integral transform has supremum bound f1 (The L1 transform is bounded and uniformly continuous).

[F3]

One smooth compactly supported sequence approximates f in both norms (Simultaneous L1 and L2 smooth approximation).

[F4]

Complex norm convergence has an almost-everywhere convergent subsequence of representatives with the correct limit class (Complex completeness, density, and inner product: the consumer interface).

Proof

technique · direct
1.1

Choose the sequence fj of [F3]. Its terms are Schwartz, since every weighted derivative has compact support and is bounded. Thus [F1] identifies F2fj with the class of f^j. Also f^jf^fjf10 by [F2], whereas F2fjF2f in norm by [F1].

F1F2F3
2.1

By [F4], a subsequence of the transform classes has measurable representatives tending a.e. to a representative h of F2f. Those representatives and the continuous functions f^j agree off a countable union of measurable null sets, so the corresponding subsequence of f^j also tends to h a.e. Step 1.1 gives its pointwise limit f^ at every point by uniform convergence. Uniqueness of complex limits gives h=f^ a.e. Countable choice is inherited from [F3], [F4] and Plancherel; no pointwise convergence of an arbitrary norm-convergent sequence is assumed.

step 1.1F3F4given

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