Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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L2 Fourier inversion

Statement

Assume countable choice. On complex L2, F22f=Rf, Rf(x)=f(x), and F21=RF2. For fL2, the truncated integrals xRf(x)e2πixξdx converge in L2 to F2f as R. The corresponding positive-sign integrals converge in L2 to F21f. No pointwise convergence is asserted.

Facts & Assumptions

[F1]

Plancherel is unitary and obtained by Schwartz approximation (Plancherel theorem).

[F3]

Integral and norm transforms agree on the intersection (Agreement of the integral and L2 transforms).

[F6]

Dominated convergence holds (Dominated convergence).

[F7]

The complex integral substitution formula applies to a C1 diffeomorphism (A C^1 diffeomorphism satisfies the change-of-variables formula for L^1 functions).

Proof

technique · direct
1.1

Apply substitution to f2 with the C1 diffeomorphism xx, whose absolute Jacobian is one. It gives Rf2=f2 and preserves null equivalence, so R is an isometry on classes with R2=I. For Schwartz approximants ujf supplied in [F1], [F2] gives F22uj=Ruj. Both sides converge in norm by [F1] and the reflection isometry, hence F22f=Rf. Associativity then gives F2R=RF2 and both inverse identities for RF2.

F1F2F7given
2.1

The closed ball BR={xR} is measurable and finite-measure by [F4]. Thus for fR=1BRf, [F5] gives fR1λ(BR)1/2f2, and fRL2 as well. [F6] applied to the explicit integer tails of f2 gives fRf20 for all real R by monotonicity between integers. By [F3], its integral transform is F2fR, and [F1] gives error norm F2fRF2f2=fRf20. The positive-sign integral is the reflection of this integral transform; step 1.1 gives its limit RF2f=F21f.

step 1.1F1F3F4F5F6

Depends on

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Sources