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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-27
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L1 of a locally compact group is a Banach star-algebra

Statement

Assume AC. Let G be an LCH group with a fixed left Haar measure μ. Then L1(G)=L1(G,μ;C), with the convolution of Convolution on L1 of a locally compact group and the involution of Involution on L1 of a locally compact group, is a complex Banach ∗-algebra without a required unit (Banach star-algebra without a required unit).

Facts & Assumptions

Given: An LCH group G with a fixed left Haar measure μ, the complex space L1(G) with norm ∥⋅∥1, its convolution and its involution, and AC.

[F2]

Convolution on L1(G) is the unique C-bilinear extension of the Cc convolution satisfying ∥f∗g∥1≤∥f∥1∥g∥1, hence jointly continuous (Convolution on L1 of a locally compact group).

[F3]

The Cc convolution is associative: (f∗g)∗h=f∗(g∗h) for f,g,h∈Cc(G), and f∗g∈Cc(G) (Convolution preserves compact support and is associative, Compactly supported convolution on a group).

[F4]

The involution of L1(G) is conjugate-linear and isometric, satisfies (f∗)∗=f, and reverses convolution: (f∗g)∗=g∗∗f∗ for all f,g∈L1(G) (The L1 involution is isometric, involutive and reverses convolution, Involution on L1 of a locally compact group).

[F6]

A complex Banach ∗-algebra without a required unit is a possibly nonunital complex Banach algebra with a conjugate-linear involutive involution reversing products and continuous; continuity of the involution and a unit are not part of the structural claims beyond what is listed (Banach star-algebra without a required unit).

[A1]

AC is assumed in the choice-function form of the cited definition, inherited from the Haar measure and the interfaces used in [F1]–[F4]; its first use in the proof is the density statement [F5] in step 1.1 (The Axiom of Choice).

Proof

technique · direct
1.1

Associativity of convolution on L1(G). Let F,G∈L1(G) and h∈Cc(G), and choose fn,gn∈Cc(G) with fn→F and gn→G in ∥⋅∥1, possible by [F5] under the AC of [A1]. By [F2] the products converge: fn∗gn→F∗G and gn∗h→G∗h. Applying [F2] again, (fn∗gn)∗h→(F∗G)∗h and fn∗(gn∗h)→F∗(G∗h). By [F3] the two sequences are equal termwise, so their limits are equal: (F∗G)∗h=F∗(G∗h) for F,G∈L1(G) and h∈Cc(G).

A1F2F3F5
2.1

Associativity on L1(G) in the second variable as well. Let F,G,H∈L1(G) and choose hn∈Cc(G) with hn→H. By step 1.1, (F∗G)∗hn=F∗(G∗hn) for every n. By joint continuity [F2], (F∗G)∗hn→(F∗G)∗H and G∗hn→G∗H, hence F∗(G∗hn)→F∗(G∗H); uniqueness of limits gives (F∗G)∗H=F∗(G∗H).

F2F5step 1.1
3.1

The structural axioms hold. L1(G) is a complex vector space, complete and normed, with associative bilinear multiplication that is submultiplicative by [F2] and associative by step 2.1; the involution is conjugate-linear and involutive and reverses products by [F4], and it is isometric, hence in particular continuous. This is exactly the list of properties required of a complex Banach ∗-algebra without a required unit in [F6], and no unit is claimed to exist. ∎

F1F2F4F6step 2.1

Remarks

  • The involution is an isometry, not merely continuous. Property 5 of Banach star-algebra without a required unit asks only for continuity; the isometry ∥f∗∥1=∥f∥1 proved in The L1 involution is isometric, involutive and reverses convolution is stronger and is used in the approximate-identity theorem on this page.
  • Choice cost. [A1] enters only through the suppliers [F1]–[F5], namely the Haar measure, the completeness and density statements; the extension and associativity arguments in this proof use no further choice.

Depends on

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