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TheoremStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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L'Hôpital's rule for the 0/00/0 form at finite or infinite, one-sided endpoints

Statement

Let cRc\in\mathbb R and let f,gf,g be differentiable on a deleted one-sided or two-sided neighbourhood of cc, with g0g'\ne0 there. Suppose f(x)0f(x)\to0, g(x)0g(x)\to0 as xcx\to c in the chosen mode. If f(x)/g(x)LRf'(x)/g'(x)\to L\in\overline{\mathbb R}, then f(x)/g(x)Lf(x)/g(x)\to L in the same mode. The analogous statement at ++\infty or -\infty follows after the substitution t=1/xt=1/x, wherever the transformed functions are defined.

Facts & Assumptions

Given: The hypotheses and one fixed approach mode.

[L1]

Differentiability implies continuity, and the Cauchy quotient lemma gives a point between two arguments at which a secant quotient equals a derivative quotient (A function differentiable at cc is continuous at cc, Cauchy's mean-value theorem in quotient form when the denominator derivative is nonzero).

Proof

technique · direct
1.1

Extend f,gf,g to cc by f(c)=g(c)=0f(c)=g(c)=0. Their continuity at cc follows from the assumed zero limits, while differentiability gives continuity at every other point of the segment. For xcx\ne c sufficiently close, the quotient lemma on the segment with endpoints c,xc,x gives f(x)g(x)=f(ξx)g(ξx)\frac{f(x)}{g(x)}=\frac{f'(\xi_x)}{g'(\xi_x)}, where ξx\xi_x lies strictly between cc and xx.

givenL1L2
2.1

As xcx\to c in the chosen mode, ξxc\xi_x\to c in that mode. Applying the defining finite or infinite limit inequality to the derivative quotient therefore gives f(x)/g(x)Lf(x)/g(x)\to L.

step 1.1L2
3.1

At infinity, put F(t)=f(1/t)F(t)=f(1/t), G(t)=g(1/t)G(t)=g(1/t). Then F/G=f(1/t)/g(1/t)F'/G'=f'(1/t)/g'(1/t), since the common factor 1/t2-1/t^2 cancels. Apply steps 1.1 and 2.1 as t0+t\to0^+ or 00^-, and translate back.

L3step 2.1algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 74 results over 22 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources