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Lie's theorem

Statement

Let g be a finite-dimensional solvable Lie algebra over an algebraically closed field k of characteristic zero. Every nonzero finite-dimensional g-module V contains a common eigenvector: there are 0wV and χg such that yw=χ(y)w for every yg.

Facts & Assumptions

Given: The algebraically closed characteristic-zero field k, a finite-dimensional solvable k-Lie algebra g, and a nonzero finite-dimensional representation on V.

[L1]

A nonzero finite-dimensional solvable Lie algebra has a codimension-one ideal (Codimension-one ideal in a nonzero solvable Lie algebra).

[L2]

A representation is linear and satisfies [x,h]v=x(hv)h(xv) (Representations of Lie algebras).

[L3]

Every endomorphism of a nonzero finite-dimensional vector space over an algebraically closed field has an eigenvalue (Every endomorphism of a nonzero finite-dimensional vector space over an algebraically closed field has an eigenvalue).

[L4]

For finite-dimensional endomorphisms, tr(AB)=tr(BA) (For AMm×n(F) and BMn×m(F), tr(AB)=tr(BA)).

Proof

technique · induction on $\dim\mathfrak g$
1.1

If g=0, any nonzero wV is a common eigenvector with the zero functional.

basegiven
1.2

Assume g0 and the theorem for solvable Lie algebras of smaller dimension.

ihgiven
2.1

By [L1], choose a codimension-one ideal h and write g=hkx. Its derived series is contained termwise in that of g, so h is solvable. Step 1.2 gives 0vV and λh with hv=λ(h)v for every hh.

L1L2step 1.2algebra
3.1

Put Wj=span(v,xv,,xjv) and W=j0Wj; finite dimensionality makes W finite-dimensional and x-stable. Induction on j, using hxj=xjh+i=0j1xi[h,x]xj1i and [h,x]h, shows hWjWj and hxjvλ(h)xjv(modWj1). Thus W is g-stable and every hh acts upper triangularly on a basis extracted from the cyclic list, with constant diagonal λ(h).

L2step 2.1algebra
4.1

Let d=dimW>0. Because W is stable, [L2] and [L4] give 0=trW([x,h])=dλ([x,h]) for every hh, where the last equality uses the constant diagonal from step 3.1. Characteristic zero makes d1k0, so λ([x,h])=0. This is the exact use of the characteristic hypothesis.

L2L4step 3.1algebra
5.1

The nonzero common h-weight space Vλ={u:hu=λ(h)u for all hh} contains v. It is x-stable: for uVλ, [L2] and step 4.1 give h(xu)=x(hu)+[h,x]u=λ(h)xu+λ([h,x])u=λ(h)xu.

L2step 2.1step 4.1algebra
6.1

By algebraic closure and [L3], xVλ has a nonzero eigenvector w, say xw=aw. Then hw=λ(h)w for hh, and for y=h+tx we have yw=(λ(h)+ta)w. This defines the required linear functional χ. Algebraic closure is used only in [L3], characteristic zero only in step 4.1, and all choices are a finite sequence of existential choices rather than AC.

L3step 2.1step 5.1discharge-induction

Depends on

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