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Equivalent local characterizations of Dedekind domains

Statement

Assume the Axiom of Choice. Let R be a Noetherian domain that is not a field. The following are equivalent:

  1. R is a Dedekind domain.
  2. For every nonzero prime ideal p of R, the localisation Rp is a discrete valuation ring.
  3. Every nonzero proper ideal of R becomes principal after localising at each maximal ideal.

Under these equivalent conditions, every nonzero prime ideal of R is maximal.

Facts & Assumptions

Given: A Noetherian domain R that is not a field.

[F1]

A Dedekind domain is a Noetherian integrally closed domain of Krull dimension 1 (Dedekind domains).

[L1]

If R is Dedekind, then Rp is a DVR for every nonzero prime ideal p (Localizing a Dedekind domain at a nonzero prime gives a DVR).

[L2]

If each nonzero-prime localisation is a DVR, then R is integrally closed (Local DVRs at the nonzero primes force global normality).

[L3]

If each nonzero-prime localisation is a DVR, then every nonzero prime of R is maximal and dimR=1 (Local DVRs at the nonzero primes force dimension one).

[L4]

Every nonzero ideal of a DVR is principal (Ideals in a DVR are powers of the maximal ideal).

[L5]

A nonfield domain is a DVR exactly when it is a local PID with nonzero maximal ideal (Equivalent characterizations of a DVR).

[L6]

Localisations of Noetherian rings are Noetherian (Every quotient and every localisation of a Noetherian ring is Noetherian).

[L7]

Localising at a prime ideal produces a local ring (Rp is local with unique maximal ideal pRp).

Proof

technique · direct
1.1

If R is Dedekind, then [L1] gives that each localisation at a nonzero prime is a DVR. This proves (1)(2).

L1given
1.2

Assume (2). Then [L2] makes R integrally closed, and [L3] gives dimR=1 together with maximality of the nonzero primes. Because R was assumed Noetherian and nonfield, [F1] now says that R is Dedekind. This proves (2)(1).

F1L2L3given
1.3

Still assuming (2), let I be a nonzero proper ideal and let m be a maximal ideal. If Im, then Im=Rm because some element of I becomes a unit. If Im, then m is nonzero and [L4] applies in the DVR Rm from (2), so Im is principal. Therefore (3) holds.

L3L4givenalgebra
1.4

Assume (3), and let m be a maximal ideal. By [L6] and [L7], the ring Rm is a Noetherian local domain. Let JRm be a nonzero proper ideal, and let I:={rR:r/1J}. Then J=IRm, and I is a nonzero proper ideal contained in m. Applying (3) at the maximal ideal m shows that J=Im is principal. Hence every nonzero proper ideal of the local domain Rm is principal, and because R is not a field its maximal ideal mRm is nonzero. Therefore [L5] makes Rm a DVR. Now let p be a nonzero prime ideal and choose a maximal ideal mp. In the DVR Rm, the extended ideal pRm is a nonzero prime ideal, so it equals the maximal ideal mRm. Contracting to R gives p=m, so every nonzero prime is maximal and therefore Rp is a DVR by the first part applied with m=p. This proves (3)(2).

L5L6L7givenalgebra
2.1

By [L3], any of the equivalent conditions forces every nonzero prime ideal of R to be maximal.

L3step 1.1step 1.2step 1.4

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