Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (z-ai/glm-5.2)audited 2026-07-28
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A monotone function on an interval has no discontinuity of the second kind: at every point both relevant one-sided limits exist, and an interior point c is a discontinuity exactly when lim⁡x→c−f(x)<lim⁡x→c+f(x)

Statement

Let I⊆R be order-convex (Intervals of R: the nine order-convex forms, nondegeneracy, and length) and let f:I→R be nondecreasing (Nondecreasing, increasing (strictly increasing), nonincreasing, decreasing, monotone and strictly monotone real functions on a subset of R, with the dictionary to monotone sequences). Write I−=I∩(−∞,c) and I+=I∩(c,∞) for c∈I.

  1. At every c∈I, each of the two one-sided limits that is well posed exists (The left and right limits of f at c, as limits of the restrictions of f to A∩(−∞,c) and A∩(c,∞)). Consequently f has no discontinuity of the second kind (Discontinuity of f at a point of its domain, and its classification: removable discontinuity, jump discontinuity and essential discontinuity, equivalently Rudin's discontinuities of the first and of the second kind): every discontinuity of f is of the first kind.
  2. Call c∈I an interior point of I when both I− and I+ are nonempty. At such a point lim⁡x→c−f(x)  ≤  f(c)  ≤  lim⁡x→c+f(x), and f is continuous at c (Continuity of f:A→R at a point of A and on A: the ε-δ condition, its agreement with lim⁡x→cf(x)=f(c) at a limit point, and continuity at an isolated point) if and only if lim⁡x→c−f(x)=lim⁡x→c+f(x).
  3. Hence an interior point c is a discontinuity of f exactly when lim⁡x→c−f(x)  <  lim⁡x→c+f(x), and every such discontinuity is a jump, of jump lim⁡x→c+f(x)−lim⁡x→c−f(x)>0.

The same three claims hold for a nonincreasing f, with the two one-sided limits exchanged and all inequalities reversed, by applying the above to −f, which is nondecreasing (Nondecreasing, increasing (strictly increasing), nonincreasing, decreasing, monotone and strictly monotone real functions on a subset of R, with the dictionary to monotone sequences) and has exactly the same points of continuity, since ∣(−f)(x)−(−f)(c)∣=∣f(x)−f(c)∣.

A point of I that is not interior is an endpoint, and there are at most two. I−=∅ says that c is a least element of I and I+=∅ that it is a greatest one, and a set has at most one of each. Those two points are excluded from claims 2 and 3 only because a comparison of two one-sided limits is not available there; claim 1 covers them.

Facts & Assumptions

Given: An order-convex I⊆R, a nondecreasing f:I→R, and c∈I.

[L1]

If I−≠∅ then c is a limit point of I− and lim⁡x→c−f(x)=sup⁡{f(x):x∈I,x<c}≤f(c); if I+≠∅ then c is a limit point of I+ and lim⁡x→c+f(x)=inf⁡{f(x):x∈I,x>c}≥f(c) (One-sided limits of a monotone function always exist: for f nondecreasing on an interval I and c∈I, lim⁡x→c−f(x)=sup⁡{f(x):x∈I, x<c} whenever I has points below c, lim⁡x→c+f(x)=inf⁡{f(x):x∈I, x>c} whenever it has points above c, and these satisfy lim⁡x→c−f(x)≤f(c)≤lim⁡x→c+f(x)).

[L2]

If c is a limit point of both I− and I+, then lim⁡x→cf(x)=L holds if and only if both one-sided limits at c exist and equal L; in particular the two-sided limit exists exactly when the two one-sided limits exist and agree (If c is a limit point of the domain from both sides, the limit exists iff both one-sided limits exist and agree).

[L4]

A discontinuity at a two-sided point is of the second kind when at least one one-sided limit fails to exist, of the first kind otherwise, and is a jump when the two one-sided limits exist and differ; at a one-sided point it is of the first kind when the one available one-sided limit exists (Discontinuity of f at a point of its domain, and its classification: removable discontinuity, jump discontinuity and essential discontinuity, equivalently Rudin's discontinuities of the first and of the second kind).

Proof

technique · direct
1.1

Let c∈I. If I−≠∅ then lim⁡x→c−f(x) exists, and if I+≠∅ then lim⁡x→c+f(x) exists; if one of the two sets is empty the corresponding symbol is not defined and there is nothing to prove for it.

L1
2.1

Claim 1 follows: at every point of I every well-posed one-sided limit of f exists, so no discontinuity of f can be of the second kind, and every discontinuity is therefore of the first kind.

step 1.1L4
2.2

Now let c be an interior point of I, and write L−:=lim⁡x→c−f(x) and L+:=lim⁡x→c+f(x), both of which exist by step 1.1. Then L−≤f(c)≤L+, which is the displayed inequality of claim 2.

step 1.1L1
3.1

Suppose L−=L+. Then L−≤f(c)≤L+=L− forces L−=f(c)=L+, so both one-sided limits equal f(c); hence lim⁡x→cf(x) exists and equals f(c), and f is continuous at c.

step 2.2L2L3
3.2

Suppose conversely that f is continuous at c. Since c is a limit point of I− and hence of I, continuity gives lim⁡x→cf(x)=f(c), and then both one-sided limits exist and equal f(c); in particular L−=L+.

step 2.2L1L2L3
4.1

Claim 2 is proved by steps 3.1 and 3.2 together with step 2.2.

step 2.2step 3.1step 3.2
5.1

Claim 3: at an interior point c, f is discontinuous exactly when L−≠L+, and since L−≤f(c)≤L+ the only way for them to differ is L−<L+. Both one-sided limits exist and differ, so the discontinuity is a jump, of jump L+−L−>0.

step 2.2step 4.1L4∎

Remarks

  • Nothing here counts the discontinuities. Claim 3 says only what a discontinuity of a monotone function looks like at an interior point. That the set of them is at most countable is a further theorem, Froda's theorem: the set of discontinuities of a monotone function on an interval is at most countable, the injection into N being built from one fixed enumeration of the rationals by least index, so no choice principle is used, and its proof is exactly the observation that the open intervals (lim⁡x→c−f(x),lim⁡x→c+f(x)) attached to distinct discontinuities are disjoint.

  • Why no interior discontinuity of a monotone function is removable. Claim 2 rules them out at interior points: there L−=L+ already forces continuity, because the inequality L−≤f(c)≤L+ pins f(c) between the two one-sided values. That inequality is special to monotone functions, and it is what makes jump the only kind of interior discontinuity available. At a point of I that is not interior the inequality is one-sided too and the argument does not apply, so a monotone function may fail to be continuous at an endpoint of I while having its one one-sided limit; that failure is a discontinuity of the first kind and it is not a jump, there being only one side to compare.

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Sources