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TheoremStatement: Literature-sourcedProof: AI-adaptedverified 2026-09-23 (gpt-6-sol)
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Multiplicity under parameter reduction with annihilator correction

Statement

Assume the Axiom of Choice.

Let (R,m) be a Noetherian local ring, let M≠0 be a finite R-module, and put d=dim⁡Supp⁡(M). Assume d≥1 and let x,x2,…,xd be a system of parameters for M. Put Q=(x,x2,…,xd) and Q′=(x2,…,xd). For a finite module N on which J is an ideal of definition, and for an integer r≥0 with either N=0 or r≥deg⁡PJ,N, write eJ[r](N):=r! [nr]PJ,N(n), with value 0 when N=0 or deg⁡PJ,N<r. Then eQ[d](M)=eQ′[d−1](M/xM)−eQ′[d−1](0:Mx). In particular, if x is M-regular, then eQ(M)=eQ′(M/xM).

Facts & Assumptions

Given: The Axiom of Choice (The Axiom of Choice), a Noetherian local ring (R,m), a nonzero finite R-module M of support dimension d≥1, and a system of parameters x,x2,…,xd as above.

[L1]

The degree of a nonzero finite module's Hilbert-Samuel polynomial equals its support dimension under AC (The degree of the Hilbert-Samuel polynomial equals the dimension of the support).

[L2]

For a finite module and an ideal of definition generated by r elements, its degree-r coefficient is the Euler characteristic of the Koszul complex; in particular its polynomial has degree at most r (degree-r Hilbert–Samuel coefficient as Koszul Euler characteristic).

[L3]

When M/(x,Q′)M has finite length, the quotient C=M/xM and annihilator K=0:Mx each have Q′-quotients of finite length, and their Koszul Euler characteristics satisfy the first-element subtraction formula (koszul euler characteristic first element reduction).

[L4]

Degree-indexed multiplicity and Koszul Euler characteristic use the displayed polynomial and homological sign conventions (koszul euler characteristic and degree indexed multiplicity).

Proof

technique · direct
1.1L2L3given

Put K=(0:Mx) and C=M/xM. The parameter hypothesis gives finite length of M/QM, so [L3] makes Q′ a module-relative ideal of definition for both C and K (including the zero-module case). The (d−1)-generator degree bound in [L2] gives deg⁡PQ′,C,deg⁡PQ′,K≤d−1 whenever the polynomials are nonzero.

2.1L2L3L4step 1.1

By [L2], eQ[d](M)=χ(K(x,x2,…,xd;M)). The exact first-element reduction [L3] makes this χ(K(x2,…,xd;C))−χ(K(x2,…,xd;K)). Apply [L2] to each Q′-complex, with the degree-indexed convention [L4], to obtain eQ[d](M)=eQ′[d−1](C)−eQ′[d−1](K).

3.1L1step 1.1step 2.1algebra

If x is M-regular, then K=0. By [L1], deg⁡PQ,M=d, so eQ[d](M)=eQ(M)≠0. Step 2.1 therefore makes eQ′[d−1](C) nonzero. The degree bound in step 1.1 forces deg⁡PQ′,C=d−1, and hence eQ′[d−1](C)=eQ′(C). This proves eQ(M)=eQ′(M/xM).

4.1step 2.1step 3.1∎

Therefore the parameter-reduction formula holds.

Depends on

Used by

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