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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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NMSC gives an inner model with a measurable cardinal

Statement

ZFC+NMSC proves that there is an inner model with a measurable cardinal, where NMSC is the assertion that every normal Moore space is metrizable and an inner model is a transitive class model of ZFC containing all ordinals (Semantic and formal inner-model theorem for L).

Facts & Assumptions

Given: The hypothesis NMSC over ZFC.

[F1]

If there is no inner model with a measurable cardinal, then ZFC proves HYP with the parameters the construction consumes (No inner measurable implies Fleissner's HYP, Fleissner's HYP covering interface).

[F2]

HYP proves that there is a normal nonmetrizable Moore space (HYP produces a normal nonmetrizable Moore space, Moore spaces and developments).

[F3]

Such a space is a counterexample to NMSC. [given]

Proof

technique · contrapositive
1.1

Argue contrapositively inside ZFC: assume there is no inner model with a measurable cardinal.

contrapositive-reduceassume-hypgiven
2.1

By [F1] the assumption implies HYP with a fixed parameter triple κ,(κn),E and fixed ladders.

step 1.1F1
3.1

By [F2] applied to those parameters there is a normal nonmetrizable Moore space.

step 2.1F2
4.1

That space violates NMSC by [F3]. Hence the assumption of step 1.1 implies the negation of NMSC; contraposition gives that NMSC implies the existence of an inner model with a measurable cardinal.

step 3.1F3discharge-contrapositive

Remarks

  • The inner model is not constructed by the topological argument. The topological half produces a counterexample to NMSC from HYP; the existence of the inner model is the contrapositive of the covering-theoretic half (No inner measurable implies Fleissner's HYP). No claim is made here that the space or its construction yields a measurable cardinal.

Depends on

Used by

Dependency tree · two levels

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Sources