Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-02
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A convex function on an open interval has finite left and right derivatives everywhere, with f−′(u)≤f+′(u)≤(f(v)−f(u))/(v−u)≤f−′(v)≤f+′(v) for u<v

Statement

If f:I→R is convex on an open interval, then f−′(c) and f+′(c) are finite for every c∈I. Moreover, for u<v in I,

f−′(u)≤f+′(u)≤f(v)−f(u)v−u≤f−′(v)≤f+′(v).

Facts & Assumptions

Proof

technique · direct
1.1

For fixed c∈I, the functions x↦s(x,c) on x<c and x↦s(c,x) on x>c are nondecreasing by [L1]; choosing points on both sides of c, [L1] bounds each near c between two fixed finite outer secant slopes.

L1L2
2.1

The monotone one-sided-limit theorem [L3] therefore supplies finite one-sided limits of these two slope functions at c, and [L2] identifies them respectively with f−′(c) and f+′(c).

step 1.1L2L3
3.1

Apply [L1] to x<u<v and let x→u−, then to u<v<z and let z→v+; together with s(u,v)≤f−′(v) and f+′(u)≤s(u,v) obtained in the same way, this gives the displayed chain.

step 1.1step 2.1L1∎

Depends on

Used by

Dependency tree · two levels

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Sources