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Remap error separates source, target and geometry approximation

Statement

Assume Countable Choice. Let Ω^ be bounded, let Φ,Φh be the geometry maps of Curved-domain geometry approximation errors and assume each is a global orientation-preserving C1 diffeomorphism from Ω^ onto its image, with Jh≤J∗ and u is Lu-Lipschitz on the union of their images. On Ωh=Φh(Ω^) let S=(Si)i=1m and T=(Tj)j=1n be finite families of Lebesgue-measurable sets of positive measure satisfying ∣Ωh∖⋃iSi∣=∣Ωh∖⋃jTj∣=0,∣Si∩Si′∣=0 (i≠i′),∣Tj∩Tj′∣=0 (j≠j′). Thus each family is a finite measurable partition up to null sets as required by Intersection-volume conservative remapping. Let vS be source-piecewise-constant data with finite L2 error. Assume the exact target projection error below is finite. Define PTq on each target cell by its exact cell average, ηS=∥u−vS∥L2(Ωh), and ηT=∥u−PTu∥L2(Ωh). If R is the exact overlap remap, then ∥u∘Φ−(RvS)∘Φh∥L2(Ω^,Jh)≤Lue0J∗∣Ω^∣+ηS+ηT, where e0=∥Φ−Φh∥∞ and ∥z∥L2(Ω^,Jh)2=∫Ω^∣z∣2Jh.

Facts & Assumptions

Given: Countable Choice; the exact and approximate maps; a bounded approximate Jacobian; a Lipschitz field on both images; two finite measurable families satisfying the displayed coverage and pairwise-null-overlap conditions; and source values constant on source cells.

[F1]

Curved-domain geometry approximation errors: e0=∥Φ−Φh∥∞ and Jh is the positive approximate Jacobian.

[F2]

Intersection-volume conservative remapping and Overlap remapping is an L2 projection, conservative and positive: exact overlap remapping of source constants is the target-cell average projection.

[F3]

Holder's inequality for integrals, including the endpoint cases: ∣∫Tq∣2≤∣T∣∫T∣q∣2 on every finite-volume target cell.

[F4]

A C^1 diffeomorphism satisfies the change-of-variables formula for nonnegative Lebesgue measurable functions: under Countable Choice, a C1 diffeomorphism transforms nonnegative integrals by its positive Jacobian.

[A1]

Countable Choice is assumed for the measure/projection interfaces in [F2] and change of variables in [F4] (The Axiom of Countable Choice (ACω)).

Proof

1.1F1given

The Lipschitz condition gives ∣u(Φ(X))−u(Φh(X))∣≤Lue0 for every X. Integrating its square against Jh≤J∗ gives the geometry term Lue0J∗∣Ω^∣.

1.2F3givenalgebra

For any q∈L2(Ωh) and target cell T, [F3] gives ∣T∣∣PTq∣T2=∣∫Tq∣2/∣T∣≤∫T∣q∣2. Summing over the disjoint target cells shows PT is contractive. The same averaging identity gives q−PTq orthogonal to every target-cellwise constant, so PT is the orthogonal projection.

2.1F2step 1.2algebra

By [F2], RvS=PTvS. Thus u−RvS=(u−PTu)+PT(u−vS); the two terms are orthogonal and PT is contractive by step 1.2. The first term has norm ηT and the second is at most ηS, whence ∥u−RvS∥L2(Ωh)≤ηT+ηS.

3.1F4A1step 1.1step 2.1∎

Apply [F4] separately on the finitely many mesh cells to identify the physical L2(Ωh) norm in step 2.1 with the weighted pullback norm of (u−RvS)∘Φh. The triangle inequality with step 1.1 proves the claimed bound.

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