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The dual of a quotient is the annihilator

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let G be a locally compact Hausdorff abelian group and let H≤G be a closed subgroup. Then the pullback of the quotient homomorphism q:G→G/H, q^:G/H^→G^,q^(χ):=χ∘q, is an isomorphism of topological groups onto the annihilator H⊥ (The annihilator of a subgroup), which is therefore a closed subgroup of G^ topologically isomorphic to G/H^. The Axiom of Choice is used exactly as in the published compact-lift theorem for closed-subgroup quotients quoted below, and in no other place.

Facts & Assumptions

Given: A locally compact Hausdorff abelian group G, a closed subgroup H≤G, and the quotient homomorphism q:G→G/H.

[F2]

The annihilator is H⊥={γ∈G^:γ(h)=1 for every h∈H}; it is a subgroup of G^ and the kernel of the restriction homomorphism G^→H^, hence closed in G^. (The annihilator of a subgroup)

[F3]

For a continuous homomorphism φ of abelian topological groups the pullback φ^(γ)=γ∘φ is a continuous group homomorphism; and for a closed subgroup H of a locally compact Hausdorff abelian group G, the pullback q^:G/H^→G^ of the quotient map is a topological group isomorphism onto H⊥={γ∈G^:γ(h)=1 for all h∈H}, a closed subgroup of G^. (Dual homomorphisms: continuity, and the annihilator of a closed subgroup, The Pontryagin dual with the compact-open topology)

Proof

1.1F1F2F3

The map q^(χ)=χ∘q is a group homomorphism: for x∈G one has q^(χ1χ2)(x)=χ1(q(x))χ2(q(x))=(q^χ1)(x)(q^χ2)(x), since evaluation is pointwise. It is continuous by the functoriality clause of [F3] applied to the continuous homomorphism q of [F1]. Its image lies in H⊥, because for h∈H one has q^(χ)(h)=χ(q(h))=χ(0)=1, and it is injective because q is surjective.

1.2F2F3

By the closed-subgroup clause of [F3] the map q^ is a topological group isomorphism from G/H^ onto H⊥, where the annihilator is the subgroup displayed in [F2] and is closed in G^.

2.1step 1.1step 1.2∎

Combining steps 1.1 and 1.2, q^:G/H^→G^ is an isomorphism of topological groups onto H⊥, and H⊥ is a closed subgroup of G^ topologically isomorphic to G/H^; this is the statement.

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