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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Property P for nontrivial knots

Statement

Assume the Axiom of Choice. Let K⊂S3 be a nontrivial smooth knot, and let p,q be coprime integers with q≠0. For the Dehn filling Yp/q=EK(p/q) whose attached solid-torus meridian is identified with p[μ]+q[λ], the fundamental group π1(Yp/q) is nontrivial.

Facts & Assumptions

Given: Full AC, a nontrivial smooth knot K⊂S3, and a nonmeridional slope p[μ]+q[λ] with gcd⁡(p,q)=1 and q≠0.

[F1]

The filling has H1(EK(p/q);Z)≅Z/∣p∣Z for p≠0, and H1(EK(p/q);Z)≅Z for p=0. First homology of knot fillings

[F2]

For a path-connected space, H1 is naturally the abelianization of its fundamental group. The first Hurewicz map is abelianization

[F3]

If ∣p∣=1 and q≠0, the filling group admits a noncyclic homomorphism to SU(2). The supplier derives this exact interface from the explicitly imported published Kronheimer–Mrowka Theorem 1, p. 741; its gauge-theoretic theorem is not claimed as locally reconstructed. Noncyclic SU(2) representations of numerator-one surgeries

[F4]

The filling is obtained by attaching a solid torus to EK along its entire boundary torus, with meridian identified with p[μ]+q[λ]. Oriented slopes and knot Dehn filling

[F5]

The chosen exterior is the complement of the interior of the closed tubular disk bundle over the connected knot K, with boundary TK=∂N(K). Knot exterior

[A1]

Full AC is the assertion that every set-indexed family of nonempty sets has a choice function. The Axiom of Choice

[L1]

Applying [A1] to the set of members of any countable family gives the countable choice function required by [F1]. The Axiom of Choice

Proof

1.1givenF4F5construct

By [F5], the chosen tubular neighbourhood is a disk bundle over the connected knot K, so its boundary TK is a circle bundle over K with connected fibres and is connected. Indeed, a separation of TK would, since every fibre is connected, split it into two saturated open sets; their projections are open by the local bundle charts, disjoint, and cover the connected base K. Since TK is a connected smooth manifold, it is path-connected. The exterior EK is a compact smooth 3-manifold with boundary TK. Because TK is connected, it lies in one component of EK. Any other component is boundaryless, hence lies in int⁡EK and is open in S3; it is also closed in S3, since it is closed in EK and EK is closed in S3 by [F5]. This contradicts connectedness of S3. Thus EK is connected and, being a smooth manifold, path-connected. By [F4], Yp/q is the union of this path-connected exterior and an attached path-connected solid torus along TK, so Yp/q is path-connected.

1.2givenF3algebra

If ∣p∣=1, the nonmeridional condition gives q≠0, and [F3] supplies a homomorphism with noncyclic image. The trivial group has only the trivial, hence cyclic, image, so π1(Yp/q) is nontrivial.

2.1givenA1L1F1F2step 1.1algebra

By [A1] and [L1], the countable-choice hypothesis of [F1] follows from the Statement, and step 1.1 verifies its connected-exterior hypothesis. If p=0, [F1] gives H1(Yp/q;Z)≅Z. If ∣p∣≥2, it gives the nonzero finite group Z/∣p∣Z. Choose any basepoint y0 of the path-connected filling. By [F2], H1(Yp/q;Z)≅π1(Yp/q,y0)ab, so in either case the fundamental group is nontrivial.

3.1givenstep 2.1step 1.2algebra∎

Coprimality leaves exactly the cases p=0, ∣p∣=1, or ∣p∣≥2, all covered by steps 2.1 and 1.2. Thus every nonmeridional filling has nontrivial fundamental group.

External dependency

The numerator-one case uses the external Kronheimer–Mrowka theorem through [F3], with its exact hypotheses and reading limits recorded in that supplier. The homology cases and the deduction of nontriviality from a noncyclic image are the local argument above.

Depends on

Used by

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Sources