Alphabeta Math
Pipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The knot-complement theorem

1 · Prerequisites

2 · Logical flowchart

3 · Definitions, theorems and proofs

DefinitionDefinition: Literature-sourcedProof: Not applicableverified 2026-10-22 (gpt-6.1-sol)Open item page →

Candidate instanton surgery-triangle input data

Definition

Assume the Axiom of Choice. Let K⊂S3 be a smooth knot with chosen exterior EK and ordered meridian-longitude basis (μ,λ). A surgery triad is a cyclically ordered triple of primitive unoriented slopes s0,s1,s∞ on ∂EK whose pairwise geometric intersection numbers are one, together with the oriented fillings Yj=EK(sj) and the three 2-handle surgery cobordisms in the cyclic order Y0→Y1→Y∞→Y0. Choose primitive representatives vj=(pj,qj) in the ordered basis (μ,λ) so that det⁡(v0,v1)=det⁡(v1,v∞)=det⁡(v∞,v0)=1; the cyclic order is the one for which this orientation convention holds. The geometric intersection number of sj and sk is ∣pjqk−pkqj∣.

For a closed oriented Riemannian 3-manifold Y, a principal SO(3)-bundle P→Y is a locally trivial bundle with fiber SO(3) and right structure-group action. A connection A is a smooth right-SO(3)-invariant horizontal distribution on P complementary to its vertical tangent spaces. In a local trivialization its curvature is FA=dA+12[A∧A]; it is flat when FA=0. Let A(P) be the space of smooth connections and let G(P) be the group of bundle automorphisms covering the identity of Y. The configuration space is the quotient B(P)=A(P)/G(P). The associated oriented rank-three real vector bundle has second Stiefel–Whitney class w2(P)∈H2(Y;Z/2).

Fix an SO(3)-invariant inner product on so(3) and normalize the Chern–Simons functional on its covering of B(P) so that its differential at A in a connection variation a is dCSA(a)=∫Y⟨a∧FA⟩. A holonomy perturbation is a finite sum of gauge-invariant terms formed by integrating smooth class functions of holonomy around a finite family of embedded loops against compactly supported smooth weights. A critical point of a perturbed Chern–Simons functional is called a perturbed flat connection. At a nondegenerate critical point, the gauge-fixed Hessian is self-adjoint; the spectral flow along a path of such Hessians is the signed count of eigenvalues crossing zero and supplies the relative grading convention. Give R×Y the product metric and orientation dt∧or(Y). Fix a holonomy perturbation fπ and write Vπ(B)=∇L2fπ(B) for its gradient. A finite-energy perturbed anti-self-dual trajectory is a gauge-equivalence class with a temporal-gauge representative A=B(t) on the pullback bundle satisfying dBdt=−(∗YFB+Vπ(B))=−∇L2(CS+fπ)(B), with specified limiting critical points β−,β+ of that same perturbed functional at the two ends, and with finite flow energy Eπ(B):=∫R∥dBdt∥L2(Y)2 dt=∫R∥∗YFB+Vπ(B)∥L2(Y)2 dt<∞. Equivalently, in this gauge its four-dimensional equation is FA++V^π(A)=0, where V^π(A)=12(dt∧Vπ(B)+∗YVπ(B)). When π=0 this reduces to the ordinary anti-self-duality equation. On a chosen real lift of the Chern–Simons functional along the trajectory, the chain rule gives d(CS+fπ)(B(t))/dt=−∥dB/dt∥L22; whenever the functional has the specified endpoint limits, the energy is their difference. For nonzero perturbations those endpoints need not be flat, so no finiteness of the unperturbed curvature integral ∫R×Y∣FA∣2 is imposed. If the analytic Fredholm construction is established, the expected dimension is the index of the gauge-fixed linearization of the perturbed equation with the stated asymptotic conditions; translation decreases dimension by one for a nonconstant trajectory.

The candidate instanton surgery-triangle input data consist of a principal SO(3)-bundle on each Yj, compatible bundle identifications on the three cobordisms, the invariant inner product and Chern–Simons normalization, the allowed perturbation class, and the grading convention. After separate proofs of analytic existence, regularity, compactness and gluing, these data may be used to define critical-point complexes and cobordism maps. Chain complexes, exactness of the three-term Floer sequence, and independence of the choices are separate theorem obligations. This definition asserts none of those analytic or Floer-theoretic conclusions.

Remarks

The ordinary closed-manifold SO(3) theory in this definition is distinct from the singular earring complex and sutured closure used for Khovanov detection. No Khovanov or singular-instanton rank detector is a logical input to Property P in the proof route considered here.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

The trefoil group is nonabelian with abelianization Z

Statement

Let T be the trefoil represented by the standard oriented three-crossing diagram below. Choose a basepoint x0∈S3∖T in the diagram's upper collar and use the common upper-collar paths from x0 to base the positive-meridian generators. Its under-arcs are labelled a,b,c so that the ordered triples (o,L,R) of over-arc, upper target under-arc and lower source under-arc are (b,c,a), (c,a,b), and (a,b,c) at the three crossings; read each triple in the orientation-preserving local chart that straightens the over-arc to point rightward. The knot group GT=π1(S3∖T,x0), where π1 is based loops modulo endpoint-fixed homotopy with multiplication by concatenation, has presentation ⟨a,b∣aba=bab⟩. This presentation denotes the free group on a,b modulo the normal closure of the displayed relation. Its abelianization, the quotient by its commutator subgroup, is isomorphic to Z, but GT is nonabelian.

The drawing shows two oriented strands crossing three times; the two bottom endpoints join to the corresponding top endpoints by the outside arcs. The white gaps mark underpasses, and each redrawn strand is over. The crossing triples in the statement fix the generator labels and local chart convention.

abc

Facts & Assumptions

Given: The standard oriented trefoil diagram, crossing labels, chosen complement basepoint, and common upper-collar paths specified in the Statement.

[F1]

For a valid finite knot diagram with chosen complement basepoint x0, the Wirtinger presentation with one positive-meridian generator for each under-arc and one crossing conjugacy relator for each crossing presents π1(S3∖T,x0) using the common upper-collar paths. Correctness of the Wirtinger presentation

[F2]

With a rightward over-strand and the common upper-collar basing paths, the upper target meridian mL and lower source meridian mR satisfy mR=momLmo−1. Local meridian conjugacy at a Wirtinger crossing

[F3]

A group presentation ⟨a,b∣r⟩ denotes the free group on a,b modulo the normal closure of r.

Proof

1.1F1F2F3givenalgebra

Applying [F2] to the three crossing triples gives a=bcb−1, b=cac−1, and c=aba−1. Substitute the third equation into the first to obtain a=baba−1b−1; right multiplication by ba gives aba=bab. Under this relation, cac−1=aba−1aab−1a−1=abab−1a−1=babb−1a−1=b, so the second crossing equation follows. Therefore eliminating c from the presentation in [F1] yields exactly ⟨a,b∣aba=bab⟩.

2.1F3step 1.1algebra

In the abelianization, the relation becomes 2[a]+[b]=[a]+2[b], hence [a]=[b]. The abelianization is the free abelian group on [a],[b] modulo this single relation, so it is Z.

3.1step 1.1algebra∎

Map a↦(12) and b↦(23) in S3. Both aba and bab map to (13), so the relation is satisfied. These two transpositions generate S3, making the homomorphism surjective. Since S3 is nonabelian, its surjective preimage GT is nonabelian.

LemmaStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

Noncyclic SU(2) representations of numerator-one surgeries

Statement

Assume the Axiom of Choice. Let K⊂S3 be a nontrivial smooth knot, and let p,q be coprime integers with ∣p∣=1 and q≠0. For the Dehn filling Yp/q=EK(p/q) whose attached solid-torus meridian is identified with p[μ]+q[λ], the fundamental group π1(Yp/q) admits a homomorphism to SU(2) with noncyclic image.

Facts & Assumptions

Given: Full AC, a nontrivial smooth knot K⊂S3, and coprime integers p,q with ∣p∣=1 and q≠0.

[F1]

External input. For a nontrivial knot K⊂S3 and rational surgery coefficient r with ∣r∣≤2, Kronheimer–Mrowka's published Theorem 1 states that the surgery group admits a homomorphism to SU(2) with noncyclic image (and consequently is not cyclic). Source: Dehn surgery, the fundamental group and SU(2), Mathematical Research Letters 11 (2004), 741–754, Theorem 1, p. 741, DOI 10.4310/mrl.2004.v11.n6.a3. This is an imported theorem, not a locally reconstructed gauge-theoretic proof.

[F2]

Rational coefficient p/q denotes filling with meridian p[μ]+q[λ] in the meridian and preferred-longitude convention; simultaneous sign change leaves the unoriented slope unchanged. Oriented slopes and knot Dehn filling Meridian and preferred longitude

[A1]

Full AC is retained as assumed in the Statement. The Axiom of Choice

Proof

1.1givenF2algebra

Since q is a nonzero integer, ∣q∣≥1. Thus r=p/q is rational and satisfies ∣r∣=1/∣q∣≤1≤2. By [F2], the manifold in the Statement is precisely the coefficient-r surgery appearing in [F1]. Both signs of r are covered by its absolute-value hypothesis.

2.1givenA1F1step 1.1∎

Apply [F1] to this nontrivial knot and this coefficient. It gives a homomorphism π1(Yp/q)→SU(2) with noncyclic image, as required.

External input and reading limits

The published primary PDF was obtained from the International Press journal archive. Theorem 1 on printed p. 741 (PDF p. 1) was read directly, including its exact nontrivial-knot and ∣r∣≤2 hypotheses and its noncyclic-image conclusion. The slope definitions and [pa+qb] filling convention on pp. 743 and 745–746 were inspected, together with the application and nonvanishing discussion on pp. 752–753. These source readings identify the imported theorem and its convention; they do not constitute a local proof audit of its gauge theory or of all its cited prerequisites.

The paper explicitly says on p. 741 that its proof avoids explicit instanton Floer homology and the Floer exact triangle, using holonomy perturbations instead. Accordingly, this item's historical identifier does not assert a general surgery-triangle or rank theorem: its full Statement is the numerator-one representation conclusion proved above from the external input. The retained singular-instanton complex and integral resolution cube keep their existing scope; neither is relabelled as supplying this closed-surgery result. Ordinary KHI nonvanishing and varying-meridian representation paths are separate inputs and are not inferred here.

TheoremStatement: Literature-sourcedProof: AI-adaptedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

Property P for nontrivial knots

Statement

Assume the Axiom of Choice. Let K⊂S3 be a nontrivial smooth knot, and let p,q be coprime integers with q≠0. For the Dehn filling Yp/q=EK(p/q) whose attached solid-torus meridian is identified with p[μ]+q[λ], the fundamental group π1(Yp/q) is nontrivial.

Facts & Assumptions

Given: Full AC, a nontrivial smooth knot K⊂S3, and a nonmeridional slope p[μ]+q[λ] with gcd⁡(p,q)=1 and q≠0.

[F1]

The filling has H1(EK(p/q);Z)≅Z/∣p∣Z for p≠0, and H1(EK(p/q);Z)≅Z for p=0. First homology of knot fillings

[F2]

For a path-connected space, H1 is naturally the abelianization of its fundamental group. The first Hurewicz map is abelianization

[F3]

If ∣p∣=1 and q≠0, the filling group admits a noncyclic homomorphism to SU(2). The supplier derives this exact interface from the explicitly imported published Kronheimer–Mrowka Theorem 1, p. 741; its gauge-theoretic theorem is not claimed as locally reconstructed. Noncyclic SU(2) representations of numerator-one surgeries

[F4]

The filling is obtained by attaching a solid torus to EK along its entire boundary torus, with meridian identified with p[μ]+q[λ]. Oriented slopes and knot Dehn filling

[F5]

The chosen exterior is the complement of the interior of the closed tubular disk bundle over the connected knot K, with boundary TK=∂N(K). Knot exterior

[A1]

Full AC is the assertion that every set-indexed family of nonempty sets has a choice function. The Axiom of Choice

[L1]

Applying [A1] to the set of members of any countable family gives the countable choice function required by [F1]. The Axiom of Choice

Proof

1.1givenF4F5construct

By [F5], the chosen tubular neighbourhood is a disk bundle over the connected knot K, so its boundary TK is a circle bundle over K with connected fibres and is connected. Indeed, a separation of TK would, since every fibre is connected, split it into two saturated open sets; their projections are open by the local bundle charts, disjoint, and cover the connected base K. Since TK is a connected smooth manifold, it is path-connected. The exterior EK is a compact smooth 3-manifold with boundary TK. Because TK is connected, it lies in one component of EK. Any other component is boundaryless, hence lies in int⁡EK and is open in S3; it is also closed in S3, since it is closed in EK and EK is closed in S3 by [F5]. This contradicts connectedness of S3. Thus EK is connected and, being a smooth manifold, path-connected. By [F4], Yp/q is the union of this path-connected exterior and an attached path-connected solid torus along TK, so Yp/q is path-connected.

1.2givenF3algebra

If ∣p∣=1, the nonmeridional condition gives q≠0, and [F3] supplies a homomorphism with noncyclic image. The trivial group has only the trivial, hence cyclic, image, so π1(Yp/q) is nontrivial.

2.1givenA1L1F1F2step 1.1algebra

By [A1] and [L1], the countable-choice hypothesis of [F1] follows from the Statement, and step 1.1 verifies its connected-exterior hypothesis. If p=0, [F1] gives H1(Yp/q;Z)≅Z. If ∣p∣≥2, it gives the nonzero finite group Z/∣p∣Z. Choose any basepoint y0 of the path-connected filling. By [F2], H1(Yp/q;Z)≅π1(Yp/q,y0)ab, so in either case the fundamental group is nontrivial.

3.1givenstep 2.1step 1.2algebra∎

Coprimality leaves exactly the cases p=0, ∣p∣=1, or ∣p∣≥2, all covered by steps 2.1 and 1.2. Thus every nonmeridional filling has nontrivial fundamental group.

External dependency

The numerator-one case uses the external Kronheimer–Mrowka theorem through [F3], with its exact hypotheses and reading limits recorded in that supplier. The homology cases and the deduction of nontriviality from a noncyclic image are the local argument above.

LemmaStatement: Literature-sourcedProof: AI-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

An S3 filling detects the meridian slope

Statement

Assume the Axiom of Choice. Let K⊂S3 be a nontrivial smooth knot and let p,q be coprime integers, not both zero. The Dehn filling EK(p/q) is homeomorphic to S3 if and only if q=0, in which case p=±1 and the slope is the meridional slope 1/0.

Facts & Assumptions

Given: Full AC, a nontrivial smooth knot K⊂S3, and a primitive surgery slope p[μ]+q[λ].

[F1]

The filling has first homology Z/∣p∣Z when p≠0 and Z when p=0. First homology of knot fillings

[F2]

Every nonmeridional filling of a nontrivial knot has nontrivial fundamental group. Property P for nontrivial knots

[F3]

The meridional slope is 1/0 up to simultaneous sign, and the filling manifold depends only on the unoriented meridian slope. Oriented slopes and knot Dehn filling

[F4]

The chosen exterior is the complement of the interior of the tubular disk bundle over the connected knot K, and its boundary TK is the associated circle bundle. Knot exterior

[A1]

Full AC is the assertion that every set-indexed family of nonempty sets has a choice function. The Axiom of Choice

[L1]

Applying [A1] to the set of members of any countable family supplies the countable choice function required by [F1]. The Axiom of Choice

Proof

1.1givenF4construct

The chosen tubular neighbourhood is a disk bundle over the connected knot K, so its boundary TK is a circle bundle over K with connected fibres and is connected. Indeed, a separation of TK would, since every fibre is connected, split it into two saturated open sets; their projections are open by the local bundle charts, disjoint, and cover the connected base K. Since TK is a connected smooth manifold, it is path-connected. The exterior EK is a compact smooth 3-manifold with boundary TK. Because TK is connected, it lies in one component of EK. Any other component is boundaryless, hence lies in int⁡EK and is open in S3; it is also closed in S3, since it is closed in EK and EK is closed in S3 by [F4]. This contradicts connectedness of S3. Thus EK is connected and, being a smooth manifold, path-connected.

2.1givenA1L1F1step 1.1algebra

Full AC [A1] supplies the countable-choice hypothesis of [F1] by [L1], and step 1.1 verifies its connected-exterior hypothesis. If EK(p/q)≅S3, its first homology vanishes. By [F1], this excludes p=0 and every ∣p∣≥2, leaving ∣p∣=1.

3.1givenF2step 2.1algebra

If additionally q≠0, the slope is nonmeridional, so [F2] gives a nontrivial fundamental group, contradicting π1(S3)=1. Hence q=0; coprimality then gives p=±1, which is the meridional slope.

4.1givenF3algebra∎

Conversely, if q=0, coprimality forces p=±1. By [F3], filling along this meridian slope is the original decomposition S3=EK∪N(K) up to the permitted solid-torus gluing, hence is homeomorphic to S3.

Diagram

The exterior EK and the inserted solid torus meet along TK. Its meridian bounds a disk in the inserted torus and is attached along pμ+qλ. When q=0, that curve is the original meridian up to orientation, so the filling restores the original tubular neighborhood. The diagram records this gluing; the homology and Property P steps above prove the uniqueness assertion without relying on the picture.

EKD2£S1TKmeridianmapstop¹+q¸q=0:p=§1,themeridional¯lling

External dependency

The nonmeridional exclusion uses Property P [F2], whose numerator-one branch explicitly imports Kronheimer–Mrowka, published Theorem 1, p. 741. Its source and reading limits are recorded in the numerator-one supplier. The homology case split and the meridional reconstruction above are retained local arguments.

TheoremStatement: AI-adaptedProof: AI-adaptedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)Open item page →

The Gordon-Luecke knot-complement theorem

Statement

Assume the Axiom of Choice. Let K,K′⊂S3 be smooth knots with chosen compact exteriors EK,EK′, and let h:EK→EK′ be a homeomorphism. Either both K,K′ are unknotted or both are nontrivial. If both are unknotted, they are ambiently equivalent, but this particular h need not preserve their knot-meridian slopes. If both are nontrivial, h(μK) is carried to μK′ by an isotopy through homeomorphisms of the boundary torus, and h extends across their tubular solid tori to a homeomorphism of pairs (S3,K)→(S3,K′); that extension preserves ambient orientation when h preserves orientation and reverses it when h reverses orientation.

Facts & Assumptions

Given: Full AC, two smooth knots in S3, chosen compact exteriors, and a homeomorphism between those exteriors.

[F1]

For a nontrivial knot, a filling of its exterior is homeomorphic to S3 only at the meridional slope. An S3 filling detects the meridian slope

[F2]

The boundary of a nontrivial knot exterior has no properly embedded compressing disk. The boundary of a nontrivial knot exterior is incompressible

[F3]

A boundary homeomorphism of solid tori whose image meridian is ambiently isotopic to the target meridian extends over the solid tori carrying core to core and with the same orientation sign. A meridian-preserving torus homeomorphism extends over a solid torus

[F4]

In the standard model U={(z,0):∣z∣=1} in the unit sphere S3⊂C2, the exterior of the radius-ϵ tube ∣w∣≤ϵ is homeomorphic to D1−ϵ22×S1 by (z,eit)↦(z,1−∣z∣2eit). Its inverse is (z,w)↦(z,w/∣w∣), and D1−ϵ22×{1} is a proper meridian disk with essential boundary. The standard circle and exterior convention are those of the knot definitions. Oriented links in the three-sphere and ambient isotopy Knot exterior

[F5]

If two normalized tubular-neighbourhood embeddings of the same compact core use the same normal bundle and induce the same normal identification, they are ambiently isotopic after shrinking near the core. Compatible tubular neighbourhoods agree near compact sets up to ambient isotopy

[F6]

The exterior is the complement of the interior of its chosen closed tubular neighbourhood; in normal-disk coordinates, the region between nested radii is a product boundary collar. Knot exterior

[F7]

A slope is an unoriented isotopy class of an essential simple closed curve on the boundary torus, and the oriented filling type is independent of the gluing map once its meridian image is fixed. Oriented slopes and knot Dehn filling

[F8]

Here “unknotted” means ambiently equivalent, after forgetting component orientation, to the standard one-component circle; ambient equivalence uses the smooth orientation-preserving ambient-isotopy convention. Oriented links in the three-sphere and ambient isotopy

[F9]

If a continuous disk map into a compact connected orientable smooth three-manifold has boundary in the relative interior of a compact connected smooth boundary subsurface with class outside a specified normal subgroup, the smooth Loop theorem supplies a smoothly properly embedded disk whose boundary has class outside that subgroup. It need not preserve the original boundary curve pointwise. Smooth Loop theorem and the smooth incompressibility criterion

[A1]

Full AC is the assertion that every set-indexed family of nonempty sets has a choice function. The Axiom of Choice

[L1]

Full AC implies countable choice by applying its choice function to any countable family of nonempty sets. The Axiom of Choice

[F10]

Each chosen exterior EJ=S3∖int⁡N(J) is a compact smooth orientable 3-manifold with boundary TJ, the boundary circle bundle of the tubular disk bundle over the connected knot J. Knot exterior Oriented links in the three-sphere and ambient isotopy

Proof

1.1givenF10construct

For each J∈{K,K′}, the boundary TJ is a circle bundle over the connected knot J with connected fibres, hence is connected: a separation would split the boundary into saturated open sets whose projections, by local bundle charts, separate J. By [F10], EJ is a compact smooth orientable 3-manifold with boundary TJ. Since TJ is connected, it lies in one component of EJ. Any other component is boundaryless, hence lies in int⁡EJ and is open in S3; it is also closed in S3, since it is closed in EJ and EJ is closed in S3 by [F10]. This contradicts connectedness of S3. Thus both exteriors are connected and, being manifolds, path-connected.

1.2givenA1F1F7constructalgebra

Suppose both knots are nontrivial and let γ be the slope represented by h(μK). Let W,W′ be the source and target filling solid tori with product coordinates. If h preserves orientation, set g(z,w)=(z,w); if h reverses orientation, set g(z,w)=(z,w‾). In either case g has the same orientation sign as h and sends the source meridian to the target meridian. If ϕ:∂W→∂EK is the source gluing map, define the target gluing map by ϕ′=h∘ϕ∘g−1. It is orientation-reversing because ϕ is and g,h have the same sign; its meridian image is h(μK), so it defines the filling along γ. The maps h and g glue to a homeomorphism of the filled manifolds. The source filling is S3, hence the target filling along γ is homeomorphic to S3. By [F1], γ is the target meridian slope; [F7] then gives the boundary isotopy in the Statement.

2.1givenA1L1F2F4F5F6F9step 1.1construct

Suppose one knot is unknotted. By [F4] its standard radius-tube exterior is a solid torus with the displayed proper meridian disk. Use the ambient isotopy in the definition of unknotted to transport its chosen tube to a tube around the standard core U. Identify the transported and standard tube domains with the same normal bundle ν(U). For each tubular embedding Φj, its differential along the zero section induces an invertible smooth bundle map Lj:ν(U)→ν(U) on the normal quotient: invertibility follows because Φj is an embedding and is the identity on the zero section. Precompose Φj with the fibrewise map Lj−1. After restricting to a common neighbourhood of the zero section, both induced normal maps are the identity; compactness of U lets us choose one such neighbourhood for the whole core. Thus the hypotheses of [F5] hold. Under [A1], [L1] supplies its countable-choice premise, so an ambient isotopy identifies the tubes after shrinking. The standard disk transfers to the smaller chosen exterior. By [F6], the region between the smaller and original tube is a product boundary collar; trim or extend the disk across the product annulus so its boundary lies on the chosen exterior torus. The resulting proper disk still has essential boundary. Pull that disk across h or h−1 into the other exterior. Its parametrization is a continuous disk map with boundary in the target torus; the boundary class remains nontrivial because the boundary restriction is a homeomorphism. If the other knot were nontrivial, apply [F9] to its compact connected orientable smooth exterior (connectedness was proved in step 1.1), the whole smooth boundary torus as the boundary subsurface, and the trivial normal subgroup. The disk boundary lies in the relative interior of that torus, so [F9] gives a new smoothly properly embedded disk with essential boundary. This contradicts [F2]. No smoothing of the homeomorphic image disk and no replacement of h by a diffeomorphism is required. Thus either both are unknotted or both are nontrivial.

3.1givenF8step 2.1construct

If both are unknotted, [F8] gives ambient equivalences from each knot to the standard unknot; composing them gives an ambient equivalence between the knots. This conclusion is independent of whether the given h preserves the knot-meridian slope.

4.1givenF3step 2.1step 1.2step 3.1construct∎

Apply [F3] to the actual boundary restriction of h and the two tubular solid tori. The extensions agree with h on the common boundary and therefore glue to a homeomorphism of pairs (S3,K)→(S3,K′). By [F3] the ambient orientation sign is the same as that of h. Together with steps 2.1, 1.2, and 3.1 this proves every case.

Diagram

For nontrivial knots, the exterior map h carries the source meridian filling to the target filling along γ. The unique-S3-filling lemma forces γ to be the target meridian, after which the meridian-preserving boundary map extends over the solid tori. The commutative square records the maps; the proof above justifies each extension without relying on the diagram.

EKEK0S3S3h¯llon¹K¯llon°=h(¹K)h[g

Proof status

The full homeomorphism statement is retained. The unknot/nontrivial category step uses the declared smooth Loop theorem on the continuous essential-boundary disk map, as written in step 2.1; it does not require a relative smoothing theorem for the given topological disk. This local repair consumes that theorem only at its stated scope and makes no new audit claim about its proof. The nontrivial branch uses Property P and the S3-filling lemma, whose numerator-one input is now explicitly supplied by the external Kronheimer–Mrowka published Theorem 1, p. 741. That imported gauge-theoretic theorem is not claimed as a local reconstruction. The local case split, filling transport, and solid-torus extension retain the full Statement above; no new audit or workflow-gate result is asserted here.

4 · Examples, counterexamples and false statements

None yet.

Sources