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QPE output law and conditional state for a spectral input

Statement

Let V be a finite-dimensional complex inner-product space, let H:V→V be Hermitian with distinct eigenvalues λ and spectral projections Pλ, and let ψ∈V be a unit vector. Run the ideal phase-estimation sampler on ψ, with unitary U whose declared phase class on PλV is θ(λ)∈R/Z. Write θˉ(λ)∈[0,1) for its unique representative, so Uv=e2πiθˉ(λ)v for v∈PλV. Write ay(λ) for the phase-register amplitude at output y when the input is in that eigenspace, so ∣ay(λ)∣2=Pθˉ(λ)(y) as in Phase-estimation finite outcome law. Then the output law is Pr⁡(Y=y)=∑λ∈σ(H)μψ({λ})Pθˉ(λ)(y). For every outcome with positive probability, the normalized conditional system vector is ψy=∑λay(λ)PλψPr⁡(Y=y). Moreover, μψ is a probability distribution and, for every g:σ(H)→C, ⟨ψ∣g(H)∣ψ⟩=∑λμψ({λ})g(λ). The conditional system is generally a coherent sum across eigenspaces, not an exact eigenspace projection.

Facts & Assumptions

Given: A finite-dimensional Hermitian H, its spectral resolution, a unit vector ψ, the ideal sampler, and its phase encoding on every eigenspace.

[F1]

A normal endomorphism is a sum of its eigenvalues times pairwise orthogonal projections, and each spectral projection is a polynomial in the endomorphism: I=∑λPλ, PλPν=0 for distinct eigenvalues, and the projections are self-adjoint.

[F2]

State-dependent spectral distribution: μψ({λ})=∥Pλψ∥2.

[F3]

Quantum phase-estimation spectral sampler and Phase-estimation finite outcome law: on an eigenvector of phase representative θˉ(λ)∈[0,1), the phase register has amplitudes ay(λ) with squared magnitudes Pθˉ(λ)(y).

[F4]

Finite projective measurements and Projective measurement outcome weights are probabilities give the computational-basis outcome probability as the squared norm of the projected vector. The readout in Quantum phase estimation specifies the Lüders branch Z↦PyZPy; on a pure input, its positive-probability branch is therefore the projected vector normalized.

[F5]

The spectral functional calculus f(T) for a normal endomorphism: g(H)=∑λg(λ)Pλ.

[F6]

Dirac Notation Conversion: ⟨ψ∣Pλ∣ψ⟩=∥Pλψ∥2 for an orthogonal projection.

Proof

1.1F1F2F5F6given

The orthogonality in [F1] gives ψ=∑λPλψ and ∥ψ∥2=∑λ∥Pλψ∥2=1. Thus the weights in [F2] are nonnegative and sum to one. By [F5]–[F6], ⟨ψ∣g(H)∣ψ⟩=∑λg(λ)⟨ψ∣Pλ∣ψ⟩=∑λμψ({λ})g(λ).

2.1F1F2F3F4step 1.1algebra

By linearity, the QPE unitary sends the initial phase state and ψ to ∑λ∑yay(λ)∣y⟩⊗Pλψ, using [F3] on each eigenspace. Projecting the phase register onto ∣y⟩ gives the system vector vy=∑λay(λ)Pλψ. Since the summands for distinct λ are orthogonal by [F1], [F4] yields Pr⁡(Y=y)=∥vy∥2=∑λ∣ay(λ)∣2∥Pλψ∥2=∑λμψ({λ})Pθˉ(λ)(y). Summing these probabilities over the finite output set gives one, as each eigenphase kernel is a measurement law.

3.1F1F3F4step 2.1algebra∎

When Pr⁡(Y=y)>0, [F4] normalizes the projected branch to vy/∥vy∥, which is the displayed formula. Its coefficients ay(λ) need not vanish outside one eigenvalue, so no exact eigenspace-collapse claim follows; the formula itself gives the precise conditional state.

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Used by

Cited to discharge well-definedness by State-dependent spectral distribution.

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