Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Phase-estimation nearest-grid and tail bounds

Statement

Let m≥1, Q=2m, and θ∈[0,1). Every nearest grid label y has Pθ(y)≥4/π2. For any η∈R with K=⌊Qη⌋≥2, Pr⁡y∼Pθ ⁣[dT(θ−y/Q)≥η]≤12(K−1). If Qθ is an integer t, then Pθ(t)=1 and all other labels have probability 0.

Facts & Assumptions

Given: m≥1, Q=2m, θ∈[0,1), and, for the tail conclusion, η∈R with K=⌊Qη⌋≥2.

[F1]

A nearest label exists and every nearest label has probability at least 4/π2 (Nearest-grid probability in phase estimation).

[F2]

The circular-distance tail for K≥2 is at most 1/(2(K−1)) (Circular-distance tail bound in phase estimation, Circular phase distance modulo one).

[F3]

Exact-grid phases are returned with probability one (Exact phase recovery on the QPE grid).

Proof

1.1givenF1

Apply [F1] to the given θ; it supplies a nearest label y and the lower bound Pθ(y)≥4/π2.

1.2givenF2

If K=⌊Qη⌋≥2, all hypotheses of [F2] hold, so the stated circular-distance tail bound follows.

2.1givenF3step 1.1step 1.2∎

If Qθ=t∈Z, [F3] gives Pθ(t)=1 and zero probability at every other label. These conclusions prove the theorem.

Depends on

Used by

Dependency tree · two levels

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Sources