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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
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Rank-one density operators are pure-state projectors

Statement

Every pure-state ray projector on a nonzero finite-dimensional complex-inner-product space is a density operator. Conversely, every rank-one density operator is the projector of a unique pure-state ray.

Facts & Assumptions

Given: A nonzero finite-dimensional complex-inner-product space H.

[F1]

Pure state and ray: a pure state is a ray represented by a unit vector's rank-one projector.

[F2]

Density operator: a density operator is non-negative with trace one.

[F3]

Ray-to-projector is well-defined and bijective: unit-vector rays correspond bijectively to rank-one orthogonal projectors, each non-negative and trace one.

[F4]

Density operators have an orthogonal spectral ensemble: a density operator is a positive-weight sum of orthogonal unit-ray projectors, with one term per positive eigenvalue and number of terms equal to its rank.

[F5]

Rank and nullity of a linear map with finite-dimensional domain: rank is the dimension of the image of a finite-dimensional linear map.

[F6]

The basis-independent trace of an endomorphism of a finite-dimensional vector space and Trace is a linear functional on Mn(F): endomorphism trace is matrix trace in a basis, and trace is linear under scalar multiplication.

Proof

1.1F1F2F3given

For any pure-state ray, [F1] gives a unit representative and [F3] makes its projector non-negative with trace one. By [F2] it is a density operator.

2.1F2F3F4F5F6algebra∎

Let ρ be a density operator whose image has dimension one by [F5]. By [F4] its spectral ensemble has exactly one positive term, so ρ=λ∣u⟩⟨u∣ for a unit u and λ>0. The trace-one condition in [F2] gives 1=tr⁡(ρ)=λtr⁡(∣u⟩⟨u∣)=λ, by [F3] and linearity [F6]. Hence ρ is the projector of [u], and the bijection in [F3] makes that ray unique.

Remarks

The spectral-ensemble route uses a finite-dimensional eigenbasis and a finite positive-eigenvalue list; no arbitrary-index choice is used.

Depends on

Used by

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Sources