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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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Rank-one top knot Floer homology detects fibering

Statement

Assume the Axiom of Choice. Let K be a null-homologous knot in a closed connected oriented 3-manifold Y, and suppose that the knot complement Y∖K is irreducible. Let F be a genus-g Seifert surface for K. If the integral top Alexander group satisfies

HFK^(Y,K,[F],g;Z)≅Z,

then Y∖K fibers over S1 with fiber F.

Facts & Assumptions

Given: Full AC, the knot, exterior, actual surface F and integral grading-g group in the Statement.

[F1]

Under full AC and exactly these geometric and integral-group hypotheses, Ni's sutured Floer and Gabai product criterion proves that the compact exterior cut along the actual F is a product sutured manifold. Its proof explicitly imports the general balanced sutured vanishing and nonproduct rank results and records Ni's corrected characteristic-pair formulation; the resolved local signed comparison and hierarchy dependencies are preserved.

Proof

technique · direct
1.1F1

Apply F1 to the actual class [F], the actual genus g and the given integral group. The cut exterior is a product F×[0,1] as a sutured manifold. In particular the two horizontal faces correspond to the two copies of the original F, rather than to a surface selected only by a genus or homology calculation.

2.1step 1.1

To restore the exterior, identify those two faces using their actual gluing map. In product coordinates this is (x,1)∼(h(x),0) for a self-homeomorphism h:F→F. Thus the exterior is the mapping torus of h. Its projection to [0,1]/(0∼1)=S1 is a surface bundle, and the seam is precisely the original embedded F.

3.1step 2.1∎

The vertical boundary is the mapping torus of ∂F. Its boundary collar extends this bundle over the deleted-knot end, giving the fibration of Y∖K with fiber the interior of F, or equivalently with compact fiber F in the compact exterior. This proves the stated fiberedness with the prescribed surface, for arbitrary Y and also for genus zero.

Depends on

Used by

Dependency tree · two levels

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Sources