Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-12
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RP admits one-sided amplification to exponentially small error

Statement

If L∈RP and k∈N, then L has a probabilistic polynomial-time decider with no false positives and false-negative probability at most 2−k.

Facts & Assumptions

Given: a language L∈RP and an integer k≥1.

[L1]

An RP machine rejects every no-instance with probability 1 and accepts every yes-instance with probability at least 1/2 (The classes RP, coRP, ZPP, BPP, and PP).

Proof

technique · direct
1.1L1givenconstruct

Let M be an RP machine for L. Run M independently k times on the same input, and accept iff at least one run accepts. This remains polynomial time because k independent repetitions of a polynomial-time machine still use polynomial time for fixed or polynomially bounded k.

2.1L1step 1.1algebra

If x∉L, then by [L1] every run rejects, so the repeated machine also rejects with probability 1. If x∈L, then each run fails to accept with probability at most 1/2, and independence makes the probability that all k runs fail at most (1/2)k=2−k.

3.1step 2.1∎

Thus the repeated machine keeps one-sided error and reduces the false negative probability to at most 2−k.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources