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Smooth-integrand variance rate for nestedly scrambled (λ,t,m,d)-nets

Statement

Assume Countable Choice. Fix b≥2, d≥1, t≥0, and 1≤λ<b. For each sufficiently large m≥t, let a1,…,an be a (λ,t,m,d)-net in base b, where n=λbm, and let X1,…,Xn be its nested uniform scramble. Suppose f is real, continuous on [0,1]d, and every nonempty mixed coordinate derivative ∂uf exists and is continuous on the cube. Then Var⁡(1n∑i=1nf(Xi))=O(n−3(log⁡n)d−1)(m→∞). The implicit constant may depend on b,d,t,λ and the suprema of the mixed derivatives; the limit is along n=λbm.

Facts & Assumptions

Given: Countable Choice, fixed b,d,t,λ, the nets and their nested scrambles, and the smooth integrand.

[F1]

ANOVA variance identity for nestedly scrambled point sets: The variance is the sum n−1∑u,κΓu,κσu,κ2(f).

[F2]

Fixed-quality net gain coefficients are uniformly bounded: For fixed b,t,d,λ, gains vanish if ∣κ∣+∣u∣≤m−t and otherwise ∣Γu,κ∣≤λbt+d−1.

[F3]

Smoothness bounds the high-frequency ANOVA components: For each u≠∅, σu,κ2(f)≤Cub−2∣κ∣ with finite Cu independent of m.

[F4]

Moments, variance, and covariance on a probability space: The target variance is the centered second moment, finite under the stated continuity.

[A1]

The Axiom of Countable Choice (ACω): Countable Choice is inherited through [F1].

Proof

technique · direct

Given: The objects and hypotheses of the Statement.

1.1A1F1F2F3F4F5

By [F5], f is bounded on the compact cube and is square-integrable; [F4] identifies its variance as the finite centered second moment. Put G=λbt+d−1. By [F1]–[F3] and nonnegativity of the component variances, Var⁡(I^n)≤Gn∑u≠∅Cu∑κ∈N∣u∣∣κ∣>m−t−∣u∣b−2∣κ∣, where each Cu is fixed independently of m.

2.1step 1.1algebra

Fix u and write p=∣u∣. The number of nonnegative p-tuples with coordinate sum r is (r+p−1p−1). For m>t+d, reindexing with s=r−(m−t−p)≥1 gives ∑∣κ∣>m−t−pb−2∣κ∣=b−2(m−t−p)∑s≥1(m−t+s−1p−1)b−2s. For fixed p,b,t, (m−t+s−1p−1)≤(m+s)p−1/(p−1)!; for m≥1, (m+s)p−1≤mp−1(1+s)p−1. The series ∑s≥1(1+s)p−1b−2s converges, so the display is O(b−2mmp−1)=O(n−2(log⁡n)p−1), since b−2m=λ2n−2 and m=log⁡b(n/λ).

3.1F3step 1.1step 2.1algebra∎

There are finitely many nonempty subsets u, with p≤d. Substituting the bounds from step 2.1 into step 1.1 gives Var⁡(I^n)=O(n−3(log⁡n)d−1). The constants depend only on the fixed parameters and the derivative bounds in [F3].

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