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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Set has all small colimits, realized as a quotient of a set-indexed disjoint union

Statement

Every small diagram D:J→Set has a colimit. It is the quotient of the tagged union S={(j,x):x∈D(j)} by the least equivalence relation containing

(j,x)∼(k,D(u)(x))(u:j→k).

Facts & Assumptions

Given: A small diagram D:J→Set.

[F1]

Smallness makes the object and morphism collections sets, and cocompleteness means existence of all small colimits (Finite, small, and large limits and colimits; complete and cocomplete categories).

[F3]

An equivalence relation is reflexive, symmetric, and transitive (Equivalence relation, equivalence class, and the quotient set A/∼).

Proof

technique · construction
1.1

By [F1], S is a set. Intersecting all equivalence relations on S that contain the displayed pairs gives the least such relation ∼; let Q=S/∼.

F1F3
2.1

Define ρj:D(j)→Q by ρj(x)=[j,x]. Each generating relation gives ρkD(u)=ρj, so ρ is a cocone.

step 1.1
2.2

For a cocone ξj:D(j)→X, define h:S→X by h(j,x)=ξj(x). The cocone equations make h equal on every generating pair, hence on the equivalence relation they generate.

givenstep 1.1
2.3

If J is empty, then S=Q=∅; the empty set has one function to every set, so the same construction is the initial-set colimit.

F2step 1.1
3.1

By [L1], there is a unique hˉ:Q→X with hˉ[j,x]=ξj(x), equivalently hˉρj=ξj for every j. Any map with these equations has the same composite with the quotient map and therefore equals hˉ.

L1step 2.2
4.1

By [F4], the cocone is colimiting. Since D was arbitrary, Set is cocomplete.

F1F4step 2.1step 3.1step 2.3∎

Depends on

Used by

Dependency tree · two levels

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Sources