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Gradient descent has vanishing gradients when the objective is bounded below along its iterates
Statement
Let , let be continuously Fréchet differentiable, and let satisfy Choose , a fixed step , and a real such that the fixed-step gradient-descent sequence satisfies for every . Then, for every integer , the following bounds hold:
- ;
- .
Moreover, as . The lower bound is required only along this sequence; the conclusion is stationarity, not convergence of the iterates or attainment of a local or global minimum.
Statement references
Facts & Assumptions
Given: The objective , its global -Lipschitz gradient, , the initial point , the fixed step , the recursively defined sequence, and the lower bound along that sequence.
Gradient descent: the fixed-step update map is ; at a stationary point its value is .
The total (Fréchet) derivative as the linear first-order approximation with remainder: total differentiability at a point means a linear first-order approximation with a remainder bounded by for every and all sufficiently small admissible increments; here means this derivative exists everywhere and varies continuously.
Descent inequality for a Lipschitz gradient: if is continuously differentiable and its gradient is -Lipschitz, then for all .
The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: for scalar-valued , is the vector of its coordinate partial derivatives.
The Euclidean inner product on : and on .
Every complete ordered field is Archimedean: in any complete ordered field , for every there is a canonical natural number with .
The reals are complete: with its usual order and field structure, the canonical real field is a complete totally ordered field, hence a complete ordered field to which [F6] applies.
Proof
Fix and put . The coordinate gradient is as in [F4], and [F1] gives .
Apply [F3] at , ; the continuously differentiable hypothesis is specified by [F2], and [F5] gives the Euclidean inner-product and norm identity. Thus , because .
Sum the inequality in step 1.2 for ; consecutive objective terms cancel, so . This proves the finite-sum bound for every .
If the gradient norms did not tend to zero, some would satisfy at infinitely many indices. The bound is real; by [F7], is a complete ordered field, so [F6] supplies a canonical natural larger than it. The infinite set of such indices contains distinct indices; take larger than all of them. Step 2.1 then gives , a contradiction. Thus ; the finite selection of indices uses no choice axiom.
For each , . Step 2.1 therefore gives the stated finite-horizon minimum-gradient bound.
Depends on
- Gradient descent
- The total (Fréchet) derivative $Df(a)$ as the linear first-order approximation with $o(\|h\|_2)$ remainder
- The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case
- The Euclidean inner product $\langle x,y\rangle = \sum_{k<n} x_k y_k$ on $\mathbb{R}^n$
- Descent inequality for a Lipschitz gradient
- Every complete ordered field is Archimedean
- The reals are complete
Used by
Dependency tree · two levels
49 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- MIT 6.7220/15.084 Nonlinear Optimization, Lecture 12: Gradient Descent and Descent Lemmas (standard reference, not scraped)
- Saeed Ghadimi and Guanghui Lan, Stochastic First- and Zeroth-Order Methods for Nonconvex Stochastic Programming (standard reference, not scraped)
- Léon Bottou, Frank E. Curtis, and Jorge Nocedal, Optimization Methods for Large-Scale Machine Learning (standard reference, not scraped)