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Gradient descent has vanishing gradients when the objective is bounded below along its iterates

Statement

Let n≥1, let F:Rn→R be continuously Fréchet differentiable, and let L>0 satisfy ∥∇F(x)−∇F(y)∥2≤L∥x−y∥2(x,y∈Rn). Choose w0∈Rn, a fixed step 0<α≤1/L, and a real F‾ such that the fixed-step gradient-descent sequence wt+1=wt−α∇F(wt) satisfies F(wt)≥F‾ for every t≥0. Then, for every integer T≥1, the following bounds hold:

  • ∑t=0T−1∥∇F(wt)∥22≤2α(F(w0)−F‾);
  • min⁡0≤t<T∥∇F(wt)∥22≤2(F(w0)−F‾)αT.

Moreover, ∥∇F(wt)∥2→0 as t→∞. The lower bound is required only along this sequence; the conclusion is stationarity, not convergence of the iterates or attainment of a local or global minimum.

Facts & Assumptions

Given: The C1 objective F, its global L-Lipschitz gradient, L>0, the initial point w0, the fixed step 0<α≤1/L, the recursively defined sequence, and the lower bound F‾ along that sequence.

[F1]

Gradient descent: the fixed-step update map is x↦x−tk∇f(x); at a stationary point its value is x.

[F2]

The total (Fréchet) derivative Df(a) as the linear first-order approximation with o(∥h∥2) remainder: total differentiability at a point means a linear first-order approximation with a remainder bounded by ε∥h∥2 for every ε>0 and all sufficiently small admissible increments; here C1 means this derivative exists everywhere and varies continuously.

[F3]

Descent inequality for a Lipschitz gradient: if f:Rn→R is continuously differentiable and its gradient is L-Lipschitz, then f(y)≤f(x)+⟨∇f(x),y−x⟩+L2∥y−x∥22 for all x,y∈Rn.

[F4]

The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case: for scalar-valued F, ∇F(x) is the vector of its coordinate partial derivatives.

[F5]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: ⟨u,v⟩=∑k<nukvk and ∥u∥22=⟨u,u⟩ on Rn.

[F6]

Every complete ordered field is Archimedean: in any complete ordered field K, for every c∈K there is a canonical natural number q≥1 with c<q⋅1K.

[F7]

The reals are complete: with its usual order and field structure, the canonical real field R is a complete totally ordered field, hence a complete ordered field to which [F6] applies.

Proof

1.1givenF1F4

Fix t≥0 and put gt=∇F(wt). The coordinate gradient is as in [F4], and [F1] gives wt+1=wt−αgt.

1.2givenF2F3F5algebra

Apply [F3] at x=wt, y=wt+1; the continuously differentiable hypothesis is specified by [F2], and [F5] gives the Euclidean inner-product and norm identity. Thus F(wt+1)≤F(wt)−α∥gt∥22+Lα22∥gt∥22≤F(wt)−α2∥gt∥22, because Lα≤1.

2.1givenstep 1.2algebra

Sum the inequality in step 1.2 for t=0,…,T−1; consecutive objective terms cancel, so α2∑t=0T−1∥∇F(wt)∥22≤F(w0)−F(wT)≤F(w0)−F‾. This proves the finite-sum bound for every T≥1.

3.1givenF6F7step 2.1assume-hypchoosealgebra

If the gradient norms did not tend to zero, some ε>0 would satisfy ∥∇F(wt)∥2≥ε at infinitely many indices. The bound 2(F(w0)−F‾)/(αε2) is real; by [F7], R is a complete ordered field, so [F6] supplies a canonical natural q larger than it. The infinite set of such indices contains q distinct indices; take T larger than all of them. Step 2.1 then gives qε2≤2(F(w0)−F‾)/α, a contradiction. Thus ∥∇F(wt)∥2→0; the finite selection of indices uses no choice axiom.

4.1step 2.1algebra∎

For each T≥1, Tmin⁡0≤t<T∥∇F(wt)∥22≤∑t=0T−1∥∇F(wt)∥22. Step 2.1 therefore gives the stated finite-horizon minimum-gradient bound.

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