Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-30
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Smooth locally defined functions can be glued by a partition of unity

Statement

Let (Ui)iI be an open cover of a smooth manifold M, let fi:UiR be smooth for each i, and let (ϕi)iI be a smooth partition of unity subordinate to (Ui). Then the pointwise formula F(p):=iϕi(p)fi(p) defines a smooth function F:MR.

Facts & Assumptions

Given: An open cover (Ui)iI of M, smooth functions fi:UiR, and a smooth partition of unity (ϕi)iI subordinate to (Ui).

[F1]

In a smooth partition of unity subordinate to (Ui), the support family (supp(ϕi)) is locally finite and each support lies in Ui (Smooth partitions of unity subordinate to an open cover).

[L1]

Smooth maps paste over an open cover (Smooth maps paste over an open cover).

[L2]

A locally finite sum of smooth functions is smooth (A locally finite sum of smooth functions is smooth).

[A1]

For each i, the product ϕifi is smooth on Ui.

Proof

technique · direct
1.1

Fix iI. On the open set Ui let Gi:=ϕifi, and on the open set Msupp(ϕi) let Hi:=0. By [A1], the map Gi is smooth on Ui; by [F1], the two open sets cover M and on the overlap Uisupp(ϕi) one has ϕi=0, so Gi=Hi. Therefore [L1] pastes them to a smooth global function Fi:MR with Fi=ϕifi on Ui and supp(Fi)supp(ϕi).

F1L1A1givenconstruct
2.1

By [F1] and step 1.1, the family (supp(Fi))iI is locally finite. Hence the sum F:=iFi is well defined and smooth by [L2].

F1L2step 1.1
3.1

Let pM. If ϕi(p)0, then pUi and step 1.1 gives Fi(p)=ϕi(p)fi(p). If ϕi(p)=0, then psupp(ϕi), so step 1.1 gives Fi(p)=0=ϕi(p)fi(p). Thus F(p)=iϕi(p)fi(p), and this pointwise formula is smooth by step 2.1.

F1step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources