TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-01

How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Symmetric and alternating images are smooth subbundles

Statement

For each $k \geq 0$ , the symmetric and alternating fibrewise parts of $T_{k}^{0} M$ form smooth vector subbundles of the covariant tensor bundle.

Facts & Assumptions

Given: A smooth manifold $M$ and an integer $k \geq 0$ .

[F1]

The symmetric and alternating parts are defined fibrewise inside the covariant tensor bundle (Symmetric and alternating covariant tensor subbundles).

[L1]

The covariant tensor bundle is a smooth vector bundle, and the fibrewise symmetrization and alternation operators are projections (Tensor transition laws define a smooth vector bundle, Symmetrization and alternation are projections).

[L2]

The image of a constant-rank bundle map over one base is a smooth vector subbundle (Constant-rank kernels and images of bundle maps over one base are subbundles).

Proof

technique · direct

1.1F1L1given

By [L1], symmetrization and alternation act fibrewise on $T_{k}^{0} M$ as smooth bundle endomorphisms over ${id}_{M}$ . Their fibres are the usual linear projections onto the symmetric and alternating tensors.

2.1L1L2step 1.1algebra

Because a projection has constant rank equal to the dimension of its image, the fibre ranks of these bundle maps are constant on $M$ . Therefore [L2] shows that their images are smooth vector subbundles.

3.1F1step 2.1∎

Those images are exactly the symmetric and alternating bundles from [F1]. Hence both are smooth vector subbundles of $T_{k}^{0} M$ .

Depends on

Used by

Cited to discharge well-definedness by Symmetric and alternating covariant tensor subbundles.

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources

John M. Lee, Introduction to Smooth Manifolds, 2nd ed. (standard reference, not scraped)