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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-09-26 (gpt-6-sol)
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The two-strand braid group is infinite cyclic

Statement

The braid group B2 is cyclic, generated by σ1, and σ1 has infinite order. Hence B2 is an infinite cyclic group.

Facts & Assumptions

Given: The Artin presentation of the braid groups.

[L1]

The group B2 is presented by one generator σ1 and no braid relations (The braid group by Artin presentation).

[L2]

In the free group on an alphabet, reduced words are the elements, the empty word is the identity, and two reduced words represent the same element only when they are identical (Reduced words form the free group on an alphabet).

Proof

technique · direct
1.1givenL1algebra

By [L1], the presentation of B2 has one generator and no defining relator, so every element of B2 is a power of σ1. Thus B2 is cyclic.

2.1L1L2step 1.1

With no relators present, the presented group is the free group on the singleton alphabet {σ1}. For m>0 the power σ1m is represented by a word of m copies of σ1; for m<0 it is represented by ∣m∣ copies of the formal inverse. Each is a nonempty reduced word, distinct from the empty identity word by [L2]. Hence σ1m≠1 for every nonzero integer m.

3.1step 1.1step 2.1∎

Therefore the cyclic group B2=⟨σ1⟩ is infinite, so it is infinite cyclic.

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources